Indefinite Integration

Basic Integration Rules

0:00
LearnStep 1/3

Basic Integration Rules

Basic Integration Rules

Namaste, JEE aspirants! Welcome to the world of integral calculus. Integration is a fundamental concept, crucial for solving a wide range of problems in JEE Main, from finding areas under curves to solving differential equations. Mastering basic integration rules is your first step towards acing calculus. Let's dive in!

1. Antiderivative: The Reverse Process

Imagine you have a function, say f(x)=2xf(x) = 2x. What function, when differentiated, gives you 2x2x? The answer is x2x^2 (because the derivative of x2x^2 is 2x2x). We call x2x^2 an antiderivative of 2x2x.

Integration is essentially finding the antiderivative. However, there's a slight twist. The derivative of x2+1x^2 + 1 is also 2x2x. Similarly, the derivative of x25x^2 - 5 is 2x2x. In fact, the derivative of x2+Cx^2 + C, where CC is any constant, is always 2x2x.

Therefore, the antiderivative is not unique; it's a family of functions differing by a constant. We represent this by adding "+ C" to the antiderivative. This "C" is called the constant of integration. So, the integral of 2x2x is x2+Cx^2 + C.

2. Power Rule: Integrating Polynomials

The power rule is your go-to tool for integrating polynomial functions. It's a direct consequence of the power rule in differentiation, but used in reverse.

xndx=xn+1n+1+C,n1\int x^n \, dx = \frac{x^{n+1}}{n+1} + C, \quad n \neq -1

Explanation: To integrate xnx^n, increase the power by 1 (making it n+1n+1) and then divide by the new power (n+1n+1). Don't forget the "+ C".

Example: Let's integrate x3x^3. Using the power rule: x3dx=x3+13+1+C=x44+C\int x^3 \, dx = \frac{x^{3+1}}{3+1} + C = \frac{x^4}{4} + C

Why n1n \neq -1? If n=1n = -1, we have x1dx=1xdx\int x^{-1} \, dx = \int \frac{1}{x} \, dx. The power rule doesn't apply here, as it would lead to division by zero. This case has its own special rule...

3. Integration of 1/x: The Natural Log

The integral of 1/x1/x (or x1x^{-1}) is the natural logarithm of the absolute value of xx.

1xdx=lnx+C\int \frac{1}{x} \, dx = \ln|x| + C

Explanation: The derivative of ln(x)\ln(x) is 1/x1/x for x>0x > 0. To handle negative values of xx, we use the absolute value. The derivative of ln(x)\ln(-x) is also 1/x1/x for x<0x < 0. Thus, using lnx\ln|x| covers both positive and negative cases.

Example: 1xdx=lnx+C\int \frac{1}{x} \, dx = \ln|x| + C

4. Integrating Exponential Functions

Exponential functions are those where the variable appears in the exponent. Integration rules vary slightly based on the base of the exponential.

a) Integrating exe^x

exdx=ex+C\int e^x \, dx = e^x + C

Explanation: The derivative of exe^x is exe^x itself! Therefore, the integral is also ex+Ce^x + C.

Example: exdx=ex+C\int e^x \, dx = e^x + C

b) Integrating axa^x (where a is a constant)

axdx=axlna+C\int a^x \, dx = \frac{a^x}{\ln a} + C

Explanation: The derivative of axa^x is axlnaa^x \ln a. Therefore, to get axa^x upon differentiation, we need to divide by lna\ln a during integration.

Example: Let's integrate 2x2^x: 2xdx=2xln2+C\int 2^x \, dx = \frac{2^x}{\ln 2} + C

5. Integrating Trigonometric Functions

Integrating trigonometric functions involves recognizing derivative-antiderivative relationships.

sinxdx=cosx+C\int \sin x \, dx = -\cos x + C

Explanation: The derivative of cosx-\cos x is sinx\sin x.

cosxdx=sinx+C\int \cos x \, dx = \sin x + C

Explanation: The derivative of sinx\sin x is cosx\cos x.

sec2xdx=tanx+C\int \sec^2 x \, dx = \tan x + C

Explanation: The derivative of tanx\tan x is sec2x\sec^2 x.

csc2xdx=cotx+C\int \csc^2 x \, dx = -\cot x + C

Explanation: The derivative of cotx-\cot x is csc2x\csc^2 x.

Important Note: Integrals of tanx\tan x, cotx\cot x, secx\sec x, and cscx\csc x require more advanced techniques (often involving substitution or trigonometric identities) and are usually covered later. For now, focus on these four basic integrals.

Tips for Solving Integration Problems

  • Simplify first: Before integrating, simplify the expression as much as possible using algebraic identities or trigonometric identities.
  • Break it down: If the integral is a sum or difference of terms, integrate each term separately. (f(x)+g(x))dx=f(x)dx+g(x)dx\int (f(x) + g(x)) dx = \int f(x) dx + \int g(x) dx
  • Check your answer: Differentiate your result. If you get back the original integrand, you've likely integrated correctly.

Common Mistakes to Avoid

  • Forgetting "+ C": Always include the constant of integration. It represents the entire family of antiderivatives.
  • Incorrect application of the power rule: Make sure n1n \neq -1. Also, double-check that you've added 1 to the exponent and divided by the *new* exponent.
  • Sign errors: Pay close attention to signs, especially when integrating trigonometric functions. Remember that sinxdx=cosx+C\int \sin x \, dx = -\cos x + C.
  • Assuming axdx=ax+C\int a^x dx = a^x + C: Remember to divide by lna\ln a when integrating axa^x.

JEE Specific Tricks

While these basic rules are fundamental, JEE problems often require clever manipulation and application. Here's a common trick:

Trick: Recognizing patterns. JEE questions often involve integrals that *look* complicated but simplify nicely using trigonometric or algebraic identities. Practice recognizing these patterns.

Example: 1sin2x+cos2xdx\int \frac{1}{\sin^2 x + \cos^2 x} \, dx might seem tricky, but since sin2x+cos2x=1\sin^2 x + \cos^2 x = 1, the integral simplifies to 1dx=x+C\int 1 \, dx = x + C.

Keep practicing, and you'll master these basic integration rules! Good luck with your JEE prep!