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JEE Main 2018
3D Geometry
3D Geometry
Medium

Question

Statement - 1 : The point A(1,0,7)A(1,0,7) is the mirror image of the point B(1,6,3)B(1,6,3) in the line : x1=y12=z23{x \over 1} = {{y - 1} \over 2} = {{z - 2} \over 3} Statement - 2 : The line x1=y12=z23{x \over 1} = {{y - 1} \over 2} = {{z - 2} \over 3} bisects the line segment joining A(1,0,7)A(1,0,7) and B(1,6,3)B(1, 6, 3)

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Solution

Key Concepts and Formulas

  • Mirror Image of a Point in a Line: A point AA' is the mirror image of a point AA with respect to a line LL if and only if two conditions are met:
    1. The line segment AAAA' is perpendicular to the line LL.
    2. The midpoint of the line segment AAAA' lies on the line LL. (This implies LL is the perpendicular bisector of AAAA').
  • Direction Ratios (DRs):
    • For a line passing through points (x1,y1,z1)(x_1, y_1, z_1) and (x2,y2,z2)(x_2, y_2, z_2), the DRs are (x2x1,y2y1,z2z1)(x_2-x_1, y_2-y_1, z_2-z_1).
    • For a line in symmetric form xx0a=yy0b=zz0c\frac{x-x_0}{a} = \frac{y-y_0}{b} = \frac{z-z_0}{c}, the DRs are (a,b,c)(a, b, c).
  • Perpendicularity Condition: Two lines with DRs (a1,b1,c1)(a_1, b_1, c_1) and (a2,b2,c2)(a_2, b_2, c_2) are perpendicular if their dot product is zero: a1a2+b1b2+c1c2=0a_1a_2 + b_1b_2 + c_1c_2 = 0.
  • Midpoint Formula: The midpoint of a line segment joining (x1,y1,z1)(x_1, y_1, z_1) and (x2,y2,z2)(x_2, y_2, z_2) is (x1+x22,y1+y22,z1+z22)\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}, \frac{z_1+z_2}{2}\right).

Step-by-Step Solution

We are given two points A(1,0,7)A(1,0,7) and B(1,6,3)B(1,6,3), and a line L:x1=y12=z23L: \frac{x}{1} = \frac{y-1}{2} = \frac{z-2}{3}. We need to evaluate the truthfulness of two statements and their relationship.

Part 1: Evaluating Statement - 1

Statement - 1 asserts that point A(1,0,7)A(1,0,7) is the mirror image of point B(1,6,3)B(1,6,3) in the line LL. To verify this, we must check both conditions for a mirror image: perpendicularity and the midpoint lying on the line.

Step 1.1: Determine the Direction Ratios (DRs) of the line segment ABAB.

  • Why this step? To check the perpendicularity condition, we need the direction ratios of the line segment connecting the two points.
  • Given points are A(1,0,7)A(1,0,7) and B(1,6,3)B(1,6,3).
  • DRsAB=(xBxA,yByA,zBzA)=(11,60,37)=(0,6,4)DRs_{AB} = (x_B - x_A, y_B - y_A, z_B - z_A) = (1-1, 6-0, 3-7) = (0, 6, -4)

Step 1.2: Determine the Direction Ratios (DRs) of the given line LL.

  • Why this step? We need the direction ratios of the mirror line to check for perpendicularity.
  • The line LL is given by x1=y12=z23\frac{x}{1} = \frac{y-1}{2} = \frac{z-2}{3}.
  • Comparing this to the standard symmetric form, the direction ratios of line LL are: DRsL=(1,2,3)DRs_L = (1, 2, 3)

Step 1.3: Check if line segment ABAB is perpendicular to line LL.

  • Why this step? This is the first crucial condition for AA to be the mirror image of BB in LL.
  • Using the perpendicularity condition a1a2+b1b2+c1c2=0a_1a_2 + b_1b_2 + c_1c_2 = 0 with DRsAB=(0,6,4)DRs_{AB} = (0, 6, -4) and DRsL=(1,2,3)DRs_L = (1, 2, 3): (0)(1)+(6)(2)+(4)(3)=0+1212=0(0)(1) + (6)(2) + (-4)(3) = 0 + 12 - 12 = 0
  • Since the sum is 00, the line segment ABAB is indeed perpendicular to the line LL.

Step 1.4: Find the midpoint of the line segment ABAB.

  • Why this step? This is the second crucial condition for AA to be the mirror image of BB in LL. The midpoint must lie on line LL.
  • Let MM be the midpoint of ABAB. Using the midpoint formula for A(1,0,7)A(1,0,7) and B(1,6,3)B(1,6,3): M=(1+12,0+62,7+32)=(22,62,102)=(1,3,5)M = \left(\frac{1+1}{2}, \frac{0+6}{2}, \frac{7+3}{2}\right) = \left(\frac{2}{2}, \frac{6}{2}, \frac{10}{2}\right) = (1, 3, 5)

Step 1.5: Check if the midpoint MM lies on the line LL.

  • Why this step? This verifies the second condition for a mirror image.
  • Substitute the coordinates of M(1,3,5)M(1,3,5) into the equation of line L:x1=y12=z23L: \frac{x}{1} = \frac{y-1}{2} = \frac{z-2}{3}.
  • For the x-coordinate: 11=1\frac{1}{1} = 1
  • For the y-coordinate: 312=22=1\frac{3-1}{2} = \frac{2}{2} = 1
  • For the z-coordinate: 523=33=1\frac{5-2}{3} = \frac{3}{3} = 1
  • Since all ratios are equal (1=1=11=1=1), the midpoint M(1,3,5)M(1,3,5) lies on the line LL.

Conclusion for Statement - 1: Both conditions for AA being the mirror image of BB in line LL are satisfied. Therefore, Statement - 1 is TRUE.

Part 2: Evaluating Statement - 2

Statement - 2 says that the line LL bisects the line segment joining A(1,0,7)A(1,0,7) and B(1,6,3)B(1,6,3).

  • Why this step? We need to determine if the line LL passes through the midpoint of ABAB.
  • A line bisects a line segment if and only if it passes through the midpoint of that segment.
  • From Step 1.4, we found the midpoint of ABAB to be M(1,3,5)M(1,3,5).
  • From Step 1.5, we verified that this midpoint M(1,3,5)M(1,3,5) lies on the line LL.
  • Since the midpoint of ABAB lies on line LL, line LL bisects the line segment ABAB.

Conclusion for Statement - 2: Statement - 2 is TRUE.

Part 3: Relationship between Statement - 1 and Statement - 2

We have determined that both Statement - 1 and Statement - 2 are true. Now, we must assess if Statement - 2 provides a correct explanation for Statement - 1.

  • Statement - 1 (A is the mirror image of B in L) requires two conditions to be met:
    1. The line segment ABAB must be perpendicular to LL.
    2. The line LL must bisect the line segment ABAB (i.e., the midpoint of ABAB lies on LL).
  • Statement - 2 only affirms the second condition: LL bisects ABAB.

While LL bisecting ABAB is a necessary condition for AA to be the mirror image of BB in LL, it is not a sufficient condition on its own. The perpendicularity condition (ABLAB \perp L) is equally essential for a mirror image. Since Statement - 2 does not encompass the perpendicularity aspect, it does not fully explain why Statement - 1 is true.

Therefore, Statement - 2 is not a correct explanation for Statement - 1.

Common Mistakes & Tips

  • Distinguish "bisects" from "perpendicular bisector": A line simply bisecting a segment only means it passes through the midpoint. A perpendicular bisector implies both bisection and perpendicularity. The mirror image concept requires the line to be a perpendicular bisector.
  • Always check both conditions for mirror image: Neglecting either the perpendicularity or the midpoint condition will lead to an incorrect conclusion.
  • Accuracy in calculations: Pay close attention to the calculation of direction ratios and midpoint coordinates, as small errors can propagate.

Summary

We systematically verified both statements. Statement - 1 is true because the line segment ABAB is perpendicular to line LL, and its midpoint lies on LL. Statement - 2 is true because the midpoint of ABAB lies on line LL, meaning LL bisects ABAB. However, Statement - 2 only covers one of the two conditions required for a mirror image (bisection), omitting the crucial perpendicularity condition. Hence, Statement - 2 is not a complete explanation for Statement - 1.

The final answer is A\boxed{A}

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