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Application of Derivatives
Application of Derivatives
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Question

A point on the parabola y2=18x{y^2} = 18x at which the ordinate increases at twice the rate of the abscissa is

Options

Solution

Key Concepts and Formulas

  • Related Rates: The rates of change of related quantities are related through differentiation, often with respect to time. If y=f(x)y = f(x) and both xx and yy are functions of tt, then dydt=dydxdxdt\frac{dy}{dt} = \frac{dy}{dx} \cdot \frac{dx}{dt}.
  • Implicit Differentiation: Differentiating an equation where variables are not explicitly isolated. For example, ddx(y2)=2ydydx\frac{d}{dx}(y^2) = 2y \frac{dy}{dx}.
  • Chain Rule: A fundamental rule in calculus that states dydx=dydt/dxdt\frac{dy}{dx} = \frac{dy}{dt} / \frac{dx}{dt}.

Step-by-Step Solution

Step 1: Express the given rate condition mathematically.

The problem states that the ordinate (y-coordinate) increases at twice the rate of the abscissa (x-coordinate). This means dydt=2dxdt\frac{dy}{dt} = 2 \frac{dx}{dt}. Our goal is to find the point (x,y)(x, y) on the parabola where this condition holds.

Why this step? This step translates the problem's verbal condition into a mathematical equation, which is the foundation for solving the problem.

dydt=2dxdt\frac{dy}{dt} = 2 \frac{dx}{dt}

Step 2: Relate the rate condition to dydx\frac{dy}{dx}.

We know that dydx\frac{dy}{dx} represents the instantaneous rate of change of yy with respect to xx. From the chain rule, we have dydx=dy/dtdx/dt\frac{dy}{dx} = \frac{dy/dt}{dx/dt}. Substituting the given condition dydt=2dxdt\frac{dy}{dt} = 2 \frac{dx}{dt} into this equation, we get:

Why this step? We want to relate the rates of change with respect to time to the derivative dydx\frac{dy}{dx}, which can be found from the parabola's equation.

dydx=2dxdtdxdt\frac{dy}{dx} = \frac{2 \frac{dx}{dt}}{\frac{dx}{dt}}

Assuming dxdt0\frac{dx}{dt} \neq 0 (otherwise, the abscissa isn't changing), we can simplify to:

dydx=2\frac{dy}{dx} = 2

This tells us that the slope of the tangent to the parabola at the desired point is 2.

Step 3: Find dydx\frac{dy}{dx} using implicit differentiation.

We are given the equation of the parabola: y2=18xy^2 = 18x. We need to find an expression for dydx\frac{dy}{dx} in terms of xx and yy. We will differentiate both sides of the equation with respect to xx.

Why this step? Implicit differentiation is used to find the derivative of yy with respect to xx when yy is not explicitly defined as a function of xx.

ddx(y2)=ddx(18x)\frac{d}{dx}(y^2) = \frac{d}{dx}(18x)

Applying the chain rule on the left side and the power rule on the right side:

2ydydx=182y \frac{dy}{dx} = 18

Now, solve for dydx\frac{dy}{dx}:

dydx=182y=9y\frac{dy}{dx} = \frac{18}{2y} = \frac{9}{y}

Step 4: Find the y-coordinate of the point.

From Step 2, we have dydx=2\frac{dy}{dx} = 2. From Step 3, we have dydx=9y\frac{dy}{dx} = \frac{9}{y}. Setting these equal to each other:

Why this step? Equating the two expressions for the slope allows us to solve for the y-coordinate.

2=9y2 = \frac{9}{y}

Solving for yy:

2y=92y = 9

y=92y = \frac{9}{2}

Step 5: Find the x-coordinate of the point.

Since the point (x,y)(x, y) lies on the parabola y2=18xy^2 = 18x, we can substitute y=92y = \frac{9}{2} into this equation to find the corresponding xx-coordinate.

Why this step? This step uses the parabola equation to find the xx-coordinate corresponding to the yy-coordinate we just found.

(92)2=18x\left( \frac{9}{2} \right)^2 = 18x

814=18x\frac{81}{4} = 18x

Solving for xx:

x=814×18=8172=9×99×8=98x = \frac{81}{4 \times 18} = \frac{81}{72} = \frac{9 \times 9}{9 \times 8} = \frac{9}{8}

Step 6: State the coordinates of the required point.

The coordinates of the point are (98,92)\left( \frac{9}{8}, \frac{9}{2} \right).

Comparing this with the given options, we find that it matches option (A).

Common Mistakes & Tips

  • Forgetting the chain rule: When implicitly differentiating, remember to apply the chain rule to terms involving yy. For example, ddx(y2)=2ydydx\frac{d}{dx}(y^2) = 2y \frac{dy}{dx}.
  • Incorrectly interpreting the rate condition: Ensure you correctly translate the given relationship between the rates of change into a mathematical equation.
  • Assuming dxdt=0\frac{dx}{dt} = 0: The problem implies that both xx and yy are changing, so dxdt\frac{dx}{dt} cannot be zero.

Summary

We started by translating the given rate condition into a mathematical equation, dydt=2dxdt\frac{dy}{dt} = 2 \frac{dx}{dt}. Using the chain rule, we found that dydx=2\frac{dy}{dx} = 2. We then used implicit differentiation on the parabola's equation to find another expression for dydx\frac{dy}{dx}, which was 9y\frac{9}{y}. Equating these two expressions allowed us to solve for yy, and substituting this value back into the parabola's equation gave us the corresponding xx value. This led us to the point (98,92)\left( \frac{9}{8}, \frac{9}{2} \right).

Final Answer

The final answer is (98,92)\boxed{\left( \frac{9}{8}, \frac{9}{2} \right)}, which corresponds to option (A).

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