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JEE Main 2023
Circles
Circle
Hard

Question

Two circles in the first quadrant of radii r1r_{1} and r2r_{2} touch the coordinate axes. Each of them cuts off an intercept of 2 units with the line x+y=2x+y=2. Then r12+r22r1r2r_{1}^{2}+r_{2}^{2}-r_{1} r_{2} is equal to ___________.

Answer: 2

Solution

Key Concepts and Formulas

  • Equation of a Circle Touching Coordinate Axes: A circle in the first quadrant touching both the x-axis and y-axis has its center at (r,r)(r, r) and radius rr. Its equation is (xr)2+(yr)2=r2(x-r)^2 + (y-r)^2 = r^2.
  • Perpendicular Distance from a Point to a Line: The perpendicular distance dd from a point (x0,y0)(x_0, y_0) to a line ax+by+c=0ax + by + c = 0 is given by d=ax0+by0+ca2+b2d = \frac{|ax_0 + by_0 + c|}{\sqrt{a^2 + b^2}}.
  • Length of Intercept by a Circle on a Line: If a circle of radius rr cuts a line, and the perpendicular distance from the center of the circle to the line is dd, then the length of the intercept is 2r2d22\sqrt{r^2 - d^2}.

Step-by-Step Solution

Step 1: Write the equation of the circles.

Since both circles touch the coordinate axes in the first quadrant, their centers are at (r1,r1)(r_1, r_1) and (r2,r2)(r_2, r_2), and their equations are: (xr1)2+(yr1)2=r12(x - r_1)^2 + (y - r_1)^2 = r_1^2 (xr2)2+(yr2)2=r22(x - r_2)^2 + (y - r_2)^2 = r_2^2

Step 2: Calculate the perpendicular distance from the center of each circle to the line x+y=2x + y = 2.

The equation of the line can be written as x+y2=0x + y - 2 = 0. The perpendicular distance d1d_1 from (r1,r1)(r_1, r_1) to the line is: d1=r1+r1212+12=2r122=2(r11)2=2r11d_1 = \frac{|r_1 + r_1 - 2|}{\sqrt{1^2 + 1^2}} = \frac{|2r_1 - 2|}{\sqrt{2}} = \frac{|2(r_1 - 1)|}{\sqrt{2}} = \sqrt{2}|r_1 - 1| Similarly, the perpendicular distance d2d_2 from (r2,r2)(r_2, r_2) to the line is: d2=r2+r2212+12=2r222=2(r21)2=2r21d_2 = \frac{|r_2 + r_2 - 2|}{\sqrt{1^2 + 1^2}} = \frac{|2r_2 - 2|}{\sqrt{2}} = \frac{|2(r_2 - 1)|}{\sqrt{2}} = \sqrt{2}|r_2 - 1|

Step 3: Use the intercept length information.

The length of the intercept cut off by each circle on the line x+y=2x + y = 2 is 2. Using the formula for the intercept length, we have: 2r12d12=22\sqrt{r_1^2 - d_1^2} = 2 2r22d22=22\sqrt{r_2^2 - d_2^2} = 2 Squaring both equations, we get: r12d12=1r_1^2 - d_1^2 = 1 r22d22=1r_2^2 - d_2^2 = 1

Step 4: Substitute the expressions for d1d_1 and d2d_2.

Substituting the expressions for d1d_1 and d2d_2 from Step 2 into the equations from Step 3, we have: r12(2r11)2=1r_1^2 - (\sqrt{2}|r_1 - 1|)^2 = 1 r22(2r21)2=1r_2^2 - (\sqrt{2}|r_2 - 1|)^2 = 1 Simplifying, we get: r122(r11)2=1r_1^2 - 2(r_1 - 1)^2 = 1 r222(r21)2=1r_2^2 - 2(r_2 - 1)^2 = 1 Expanding and simplifying further: r122(r122r1+1)=1r_1^2 - 2(r_1^2 - 2r_1 + 1) = 1 r222(r222r2+1)=1r_2^2 - 2(r_2^2 - 2r_2 + 1) = 1 r12+4r12=1-r_1^2 + 4r_1 - 2 = 1 r22+4r22=1-r_2^2 + 4r_2 - 2 = 1 So, we have two quadratic equations: r124r1+3=0r_1^2 - 4r_1 + 3 = 0 r224r2+3=0r_2^2 - 4r_2 + 3 = 0

Step 5: Solve the quadratic equations.

Both quadratic equations are the same, so r1r_1 and r2r_2 are the roots of the equation r24r+3=0r^2 - 4r + 3 = 0. Factoring the quadratic, we have: (r1)(r3)=0(r - 1)(r - 3) = 0 Thus, the roots are r=1r = 1 and r=3r = 3. Therefore, r1=1r_1 = 1 and r2=3r_2 = 3 (or vice versa).

Step 6: Calculate the required expression.

We need to find the value of r12+r22r1r2r_1^2 + r_2^2 - r_1r_2. Substituting r1=1r_1 = 1 and r2=3r_2 = 3, we get: r12+r22r1r2=(1)2+(3)2(1)(3)=1+93=7r_1^2 + r_2^2 - r_1r_2 = (1)^2 + (3)^2 - (1)(3) = 1 + 9 - 3 = 7 However, the correct answer is 2. Let's re-examine the problem. The intercept equation is 2r2d2=22\sqrt{r^2 - d^2} = 2, which implies r2d2=1r^2 - d^2 = 1. Substituting d=2r1d = \sqrt{2}|r-1|, we have r22(r1)2=1r^2 - 2(r-1)^2 = 1, which simplifies to r24r+3=0r^2 - 4r + 3 = 0. The roots are r=1,3r=1, 3. So r1=1r_1 = 1 and r2=3r_2 = 3. The expression we need to evaluate is r12+r22r1r2=12+32(1)(3)=1+93=7r_1^2 + r_2^2 - r_1 r_2 = 1^2 + 3^2 - (1)(3) = 1 + 9 - 3 = 7. There's been an error.

Let's consider the case where the intercept is 2. r22(r1)2=1r^2 - 2(r-1)^2 = 1, which gives r22r2+4r2=1r^2 - 2r^2 + 4r - 2 = 1, or r24r+3=0r^2 - 4r + 3 = 0. Then (r1)(r3)=0(r-1)(r-3) = 0 and r1=1,r2=3r_1 = 1, r_2 = 3.

Now, consider the case where the line x+y=2x+y=2 intersects the circle. The equation of the circle is (xr)2+(yr)2=r2(x-r)^2+(y-r)^2=r^2. The distance from the center to the line is d=r+r22=2r22=2r1d = \frac{|r+r-2|}{\sqrt{2}} = \frac{|2r-2|}{\sqrt{2}} = \sqrt{2}|r-1|. We have r2d2=1r^2 - d^2 = 1, so r22(r1)2=1r^2 - 2(r-1)^2 = 1, which implies r22(r22r+1)=1r^2 - 2(r^2-2r+1) = 1, so r2+4r2=1-r^2 + 4r - 2 = 1, or r24r+3=0r^2-4r+3 = 0. So r=1,3r = 1, 3.

r1=1,r2=3r_1 = 1, r_2 = 3. We want r12+r22r1r2=12+32(1)(3)=1+93=7r_1^2 + r_2^2 - r_1 r_2 = 1^2 + 3^2 - (1)(3) = 1 + 9 - 3 = 7.

The given correct answer is 2. Something is wrong. Let's work backwards. If r12+r22r1r2=2r_1^2 + r_2^2 - r_1 r_2 = 2, then r12+r22r1r2=(r1+r2)23r1r2=2r_1^2 + r_2^2 - r_1 r_2 = (r_1+r_2)^2 - 3r_1r_2 = 2. Also, r1+r2=4r_1+r_2 = 4 and r1r2=3r_1 r_2 = 3. Then 163(3)=716 - 3(3) = 7, not 2.

There must be an error with the question or the answer. Let us assume the question is correct and try a different approach. If the intercept is 2, then 4=4(r2d2)4 = 4(r^2 - d^2), so 1=r2d21 = r^2 - d^2. Thus 1=r22(r1)21 = r^2 - 2(r-1)^2, which means r24r+3=0r^2 - 4r + 3 = 0. Then r=1,3r = 1, 3. So r1=1,r2=3r_1 = 1, r_2 = 3. Then r12+r22r1r2=1+93=7r_1^2 + r_2^2 - r_1 r_2 = 1 + 9 - 3 = 7.

Common Mistakes & Tips

  • Be careful with absolute values when calculating distances.
  • Double-check your algebraic manipulations to avoid errors.
  • Remember the formula for the length of an intercept.

Summary

We found the radii of the two circles to be 1 and 3. Substituting these values into the expression r12+r22r1r2r_1^2 + r_2^2 - r_1 r_2, we get 12+32(1)(3)=1+93=71^2 + 3^2 - (1)(3) = 1 + 9 - 3 = 7. However, the correct answer provided is 2. There appears to be an error in the given correct answer. Based on the problem statement, the value of the expression is 7.

Final Answer The final answer is \boxed{7}. There seems to be an error in the provided "Correct Answer" as the correct value is 7.

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