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JEE Main 2020
Circles
Circle
Easy

Question

The tangent to the circle C 1 : x 2 + y 2 - 2x - 1 = 0 at the point (2, 1) cuts off a chord of length 4 from a circle C 2 whose center is (3, -2). The radius of C 2 is :

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Solution

Key Concepts and Formulas

  • Equation of Tangent to a Circle: The equation of the tangent to the circle x2+y2+2gx+2fy+c=0x^2 + y^2 + 2gx + 2fy + c = 0 at the point (x1,y1)(x_1, y_1) is xx1+yy1+g(x+x1)+f(y+y1)+c=0xx_1 + yy_1 + g(x+x_1) + f(y+y_1) + c = 0. For a circle x2+y2=r2x^2 + y^2 = r^2, the tangent at (x1,y1)(x_1, y_1) is xx1+yy1=r2xx_1 + yy_1 = r^2.
  • Distance from a Point to a Line: The perpendicular distance dd from a point (x0,y0)(x_0, y_0) to a line Ax+By+C=0Ax + By + C = 0 is given by d=Ax0+By0+CA2+B2d = \frac{|Ax_0 + By_0 + C|}{\sqrt{A^2 + B^2}}.
  • Relationship between Radius, Chord Length, and Distance: If rr is the radius of a circle, ll is the length of a chord, and dd is the perpendicular distance from the center of the circle to the chord, then r2=(l2)2+d2r^2 = (\frac{l}{2})^2 + d^2.

Step-by-Step Solution

Step 1: Finding the Equation of the Tangent to Circle C1C_1

  • Objective: Determine the equation of the tangent to the circle C1:x2+y22x1=0C_1: x^2 + y^2 - 2x - 1 = 0 at the point (2,1)(2, 1). This tangent will also be the chord of circle C2C_2.
  • Given Information:
    • Equation of circle C1C_1: x2+y22x1=0x^2 + y^2 - 2x - 1 = 0
    • Point of tangency: (2,1)(2, 1)
  • Procedure:
    1. Rewrite the equation of C1C_1 as x2+y2+2gx+2fy+c=0x^2 + y^2 + 2gx + 2fy + c = 0. Comparing with x2+y22x1=0x^2 + y^2 - 2x - 1 = 0, we have g=1g = -1, f=0f = 0, and c=1c = -1.
    2. Apply the tangent equation formula: xx1+yy1+g(x+x1)+f(y+y1)+c=0xx_1 + yy_1 + g(x+x_1) + f(y+y_1) + c = 0.
    3. Substitute the values: x(2)+y(1)+(1)(x+2)+(0)(y+1)+(1)=0x(2) + y(1) + (-1)(x+2) + (0)(y+1) + (-1) = 0.
    4. Simplify: 2x+yx21=02x + y - x - 2 - 1 = 0, which simplifies to x+y3=0x + y - 3 = 0 or x+y=3x + y = 3.
  • Explanation: This step finds the equation of the tangent line to C1C_1 at (2,1)(2, 1). This line is also the chord of C2C_2.

Step 2: Identifying the Chord of Circle C2C_2

  • Objective: Clearly define the equation representing the chord of circle C2C_2.
  • Procedure: As determined in Step 1, the tangent to C1C_1 serves as the chord of C2C_2.
  • Result: The equation of the chord for C2C_2 is x+y3=0x + y - 3 = 0.
  • Explanation: This step establishes the connection between the circles C1C_1 and C2C_2 through their shared chord.

Step 3: Calculating the Perpendicular Distance from the Center of C2C_2 to the Chord

  • Objective: Calculate the perpendicular distance (dd) from the center of C2C_2, which is (3,2)(3, -2), to the chord x+y3=0x + y - 3 = 0.
  • Given Information:
    • Center of C2C_2: (3,2)(3, -2)
    • Equation of the chord: x+y3=0x + y - 3 = 0
  • Procedure:
    1. Apply the perpendicular distance formula: d=Ax0+By0+CA2+B2d = \frac{|Ax_0 + By_0 + C|}{\sqrt{A^2 + B^2}}.
    2. Substitute the values: d=(1)(3)+(1)(2)312+12d = \frac{|(1)(3) + (1)(-2) - 3|}{\sqrt{1^2 + 1^2}}.
    3. Simplify: d=3232=22=22=2d = \frac{|3 - 2 - 3|}{\sqrt{2}} = \frac{|-2|}{\sqrt{2}} = \frac{2}{\sqrt{2}} = \sqrt{2}.
  • Explanation: This step determines the perpendicular distance from the center of C2C_2 to the chord, which is required to calculate the radius of C2C_2.

Step 4: Finding the Radius of Circle C2C_2

  • Objective: Calculate the radius (rr) of circle C2C_2 using the chord length and the perpendicular distance.

  • Given Information:

    • Chord length: l=4l = 4
    • Perpendicular distance: d=2d = \sqrt{2}
  • Procedure:

    1. Use the relationship r2=(l2)2+d2r^2 = (\frac{l}{2})^2 + d^2.
    2. Substitute the values: r2=(42)2+(2)2r^2 = (\frac{4}{2})^2 + (\sqrt{2})^2.
    3. Simplify: r2=(2)2+2=4+2=6r^2 = (2)^2 + 2 = 4 + 2 = 6.
    4. Therefore, r=6r = \sqrt{6}.
  • Explanation: This step uses the Pythagorean theorem relationship to find the radius of circle C2C_2 using the chord length and the distance from the center to the chord.

Step 5: Correcting the Error There was an error in the original solution. It should be r=6r = \sqrt{6}, not 2.

Common Mistakes & Tips

  • Sign Errors: Double-check the signs when substituting values into formulas, especially when dealing with negative coordinates or coefficients.
  • Formula Confusion: Ensure you are using the correct formula for the equation of a tangent and the distance from a point to a line.
  • Units: While not explicitly relevant here, always pay attention to units in geometric problems to avoid errors.

Summary

We first found the equation of the tangent to circle C1C_1 at the given point, which also serves as the chord of circle C2C_2. Then, we calculated the perpendicular distance from the center of C2C_2 to this chord. Finally, using the relationship between the radius, chord length, and perpendicular distance, we found the radius of C2C_2 to be 6\sqrt{6}.

Final Answer

The final answer is 6\boxed{\sqrt{6}}, which corresponds to option (D).

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