If a > 0 and z = a−i(1+i)2, has magnitude 52, then z is equal to :
Options
Solution
Key Concepts and Formulas
Complex Number Representation: A complex number can be represented as z=x+iy, where x is the real part and y is the imaginary part, and i=−1.
Modulus of a Complex Number: The modulus (or magnitude) of a complex number z=x+iy is given by ∣z∣=x2+y2.
Conjugate of a Complex Number: The conjugate of a complex number z=x+iy is given by z=x−iy.
Step-by-Step Solution
Step 1: Simplify the expression for z.
We are given z=a−i(1+i)2. First, we simplify the numerator:
(1+i)2=1+2i+i2=1+2i−1=2i.
So, z=a−i2i.
To express z in the form x+iy, we multiply the numerator and denominator by the conjugate of the denominator, which is a+i:
z=a−i2i⋅a+ia+i=(a−i)(a+i)2i(a+i)=a2−i22ai+2i2=a2+12ai−2=a2+1−2+2ai.
Separating the real and imaginary parts, we get:
z=a2+1−2+a2+12ai.
Step 2: Use the given magnitude of z to find a.
We are given that ∣z∣=52. Using the formula for the modulus, we have:
∣z∣=(a2+1−2)2+(a2+12a)2=(a2+1)24+(a2+1)24a2=(a2+1)24+4a2=(a2+1)24(1+a2)=a2+14=a2+12.
Now we set this equal to the given magnitude:
a2+12=52.
Squaring both sides, we get:
a2+14=52.
Cross-multiplying, we have:
20=2(a2+1).
Dividing by 2, we get:
10=a2+1.
So, a2=9, which means a=±3. Since a>0, we have a=3.
Step 3: Find the conjugate z.
Substitute a=3 into the expression for z:
z=32+1−2+32+12(3)i=10−2+106i=−51+53i.
Now, find the conjugate of z:
z=−51−53i.
Common Mistakes & Tips
Carefully handle the powers of i. Remember that i2=−1.
When rationalizing the denominator, make sure to multiply both the numerator and the denominator by the conjugate of the denominator.
Pay attention to any given conditions, such as a>0, to choose the correct value.
Summary
We simplified the complex number z, used its magnitude to find the value of a, and then calculated the conjugate z. The final answer is z=−51−53i.
The final answer is \boxed{-\frac{1}{5} - \frac{3}{5}i}, which corresponds to option (B).