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JEE Main 2020
Complex Numbers
Complex Numbers
Easy

Question

If the four complex numbers z,z,z2Re(z)z,\overline z ,\overline z - 2{\mathop{\rm Re}\nolimits} \left( {\overline z } \right) and z2Re(z)z-2Re(z) represent the vertices of a square of side 4 units in the Argand plane, then z|z| is equal to :

Options

Solution

Key Concepts and Formulas

  • Complex Number Representation: z=x+iyz = x + iy, where x=Re(z)x = \text{Re}(z) and y=Im(z)y = \text{Im}(z).
  • Conjugate: z=xiy\overline{z} = x - iy.
  • Modulus: z=x2+y2|z| = \sqrt{x^2 + y^2}. Distance between z1z_1 and z2z_2 is z1z2|z_1 - z_2|.

Step-by-Step Solution

Step 1: Represent the complex number and its conjugate. Let z=x+iyz = x + iy, where xx and yy are real numbers. Then z=xiy\overline{z} = x - iy. Explanation: This sets up the foundation by expressing the complex number in terms of its real and imaginary parts and defining its conjugate.*

Step 2: Express the vertices of the square in terms of xx and yy. The given vertices are: V1=z=x+iyV_1 = z = x + iy V2=z=xiyV_2 = \overline{z} = x - iy V3=z2Re(z)=(xiy)2x=xiyV_3 = \overline{z} - 2\text{Re}(\overline{z}) = (x - iy) - 2x = -x - iy V4=z2Re(z)=(x+iy)2x=x+iyV_4 = z - 2\text{Re}(z) = (x + iy) - 2x = -x + iy Explanation: This step simplifies the expressions for each vertex, making it easier to visualize their positions in the Argand plane.*

Step 3: Calculate the side length using the distance between adjacent vertices. The side length of the square is 4. We can use the distance between V1V_1 and V2V_2 to find a relationship between xx and yy.

V1V2=(x+iy)(xiy)=2iy=2y=4|V_1 - V_2| = |(x + iy) - (x - iy)| = |2iy| = 2|y| = 4 Therefore, y=2|y| = 2.

Similarly, we can use the distance between V1V_1 and V4V_4: V1V4=(x+iy)(x+iy)=2x=2x=4|V_1 - V_4| = |(x + iy) - (-x + iy)| = |2x| = 2|x| = 4 Therefore, x=2|x| = 2. Explanation: This step uses the given side length of the square to establish the magnitudes of the real and imaginary parts of zz.*

Step 4: Calculate the modulus of zz. z=x2+y2=(±2)2+(±2)2=4+4=8=22|z| = \sqrt{x^2 + y^2} = \sqrt{(\pm 2)^2 + (\pm 2)^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2} Explanation: This step applies the formula for the modulus of a complex number, using the values found in the previous step.*

Common Mistakes & Tips

  • Sign Errors: Be careful with signs when substituting and simplifying expressions.
  • Modulus Definition: Remember that z=x2+y2|z| = \sqrt{x^2 + y^2} and not x+yx+y.
  • Geometric Visualization: Sketching the points in the Argand plane can help in understanding the relationships and avoiding errors.

Summary

We expressed the vertices of the square in terms of the real and imaginary parts of zz. By calculating the distance between adjacent vertices and equating it to the given side length, we found that x=2|x|=2 and y=2|y|=2. Finally, we calculated the modulus of zz as z=x2+y2=22|z| = \sqrt{x^2 + y^2} = 2\sqrt{2}.

Final Answer The final answer is \boxed{2\sqrt{2}}, which corresponds to option (D).

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