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JEE Main 2019
Complex Numbers
Complex Numbers
Hard

Question

If zz is a complex number such that z1|z| \leqslant 1, then the minimum value of z+12(3+4i)\left|z+\frac{1}{2}(3+4 i)\right| is :

Options

Solution

Key Concepts and Formulas

  • Geometric Interpretation: z1z2|z_1 - z_2| represents the distance between complex numbers z1z_1 and z2z_2 in the complex plane. z|z| represents the distance of zz from the origin.
  • Triangle Inequality: For complex numbers zaz_a and zbz_b, za+zbza+zb|z_a + z_b| \leqslant |z_a| + |z_b| and zazbzazb|z_a - z_b| \geqslant ||z_a| - |z_b||.
  • Modulus of a Complex Number: If z=a+biz = a + bi, then z=a2+b2|z| = \sqrt{a^2 + b^2}.

Step-by-Step Solution

Step 1: Rewrite the Expression and Identify the Fixed Point

We are given the expression z+12(3+4i)\left|z+\frac{1}{2}(3+4 i)\right| and want to find its minimum value, subject to z1|z| \leqslant 1. We can rewrite the expression as zz0|z - z_0|, where z0=12(3+4i)z_0 = -\frac{1}{2}(3+4i). Therefore, z0=322iz_0 = -\frac{3}{2} - 2i.

Reasoning: Rewriting the expression in the form zz0|z - z_0| highlights that we are finding the distance between the complex number zz and a fixed point z0z_0. This is essential for a geometric approach.

Step 2: Calculate the Modulus of the Fixed Point

We calculate z0|z_0| to determine its distance from the origin: z0=322i=(32)2+(2)2=94+4=254=52|z_0| = \left|-\frac{3}{2} - 2i\right| = \sqrt{\left(-\frac{3}{2}\right)^2 + (-2)^2} = \sqrt{\frac{9}{4} + 4} = \sqrt{\frac{25}{4}} = \frac{5}{2} Thus, z0=52|z_0| = \frac{5}{2}.

Reasoning: Calculating z0|z_0| tells us the location of the fixed point relative to the region where zz can lie.

Step 3: Analyze the Region for z

We are given that z1|z| \leqslant 1. This means that zz lies within or on the unit circle centered at the origin. Since z0=52=2.5>1|z_0| = \frac{5}{2} = 2.5 > 1, the point z0z_0 lies outside the unit circle.

Reasoning: Since the fixed point z0z_0 is outside the region where zz can be, the minimum distance between zz and z0z_0 will not be 0. It will occur when zz is on the boundary of the region, i.e., when z=1|z|=1.

Step 4: Apply the Triangle Inequality

We want to minimize zz0|z - z_0|. Using the triangle inequality zazbzazb|z_a - z_b| \geqslant ||z_a| - |z_b||, we let za=zz_a = z and zb=z0z_b = z_0: zz0zz0|z - z_0| \geqslant ||z| - |z_0|| Substitute z0=52|z_0| = \frac{5}{2}: zz0z52|z - z_0| \geqslant \left||z| - \frac{5}{2}\right|

Reasoning: The triangle inequality provides a lower bound for the distance zz0|z - z_0|. To minimize zz0|z - z_0|, we minimize this lower bound, subject to the constraint z1|z| \leqslant 1.

Step 5: Minimize the Lower Bound

We want to minimize z52\left||z| - \frac{5}{2}\right| subject to 0z10 \leqslant |z| \leqslant 1. Let x=zx = |z|. Then we want to minimize x52\left|x - \frac{5}{2}\right| where 0x10 \leqslant x \leqslant 1. Since 52>1\frac{5}{2} > 1, the closest value to 52\frac{5}{2} in the interval [0,1][0, 1] is x=1x = 1. Therefore, the minimum value of z52\left||z| - \frac{5}{2}\right| occurs when z=1|z| = 1. Substituting z=1|z| = 1, we get: Minimum value =152=32=32= \left|1 - \frac{5}{2}\right| = \left|-\frac{3}{2}\right| = \frac{3}{2}.

Reasoning: By considering the range of possible values for z|z| and the properties of the absolute value function, we find the value of z|z| that minimizes the lower bound.

Step 6: Geometric Interpretation (Verification)

The minimum distance from any point zz within or on the unit circle to the fixed point z0z_0 occurs when zz is on the line connecting the origin to z0z_0 and z=1|z| = 1. The minimum distance is z01=521=32|z_0| - 1 = \frac{5}{2} - 1 = \frac{3}{2}.

Reasoning: This geometric argument confirms our algebraic result, providing a clear visual understanding.

Conclusion

The minimum value of z+12(3+4i)\left|z+\frac{1}{2}(3+4 i)\right| is 32\frac{3}{2}.

Common Mistakes & Tips:

  • Sign Errors: Be careful with signs when identifying the fixed point z0z_0. The expression z+P|z + P| represents the distance between zz and P-P.
  • Triangle Inequality Form: Choose the appropriate form of the triangle inequality based on whether you are finding a maximum or a minimum value. For minimums, zazbzazb|z_a - z_b| \geqslant ||z_a| - |z_b|| is usually most effective.
  • Geometric Visualization: Always try to visualize complex number problems geometrically. The modulus z1z2|z_1 - z_2| is a distance, and the condition zR|z| \leqslant R means zz is inside or on a circle of radius RR centered at the origin.

Summary

This problem demonstrates how to combine geometric intuition with the triangle inequality to find the minimum value of an expression involving complex numbers. By identifying the fixed point, its location relative to the allowed region for zz, and using the appropriate form of the triangle inequality, we systematically determined that the minimum value is 32\frac{3}{2}.

The final answer is \boxed{\frac{3}{2}}, which corresponds to option (C).

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