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JEE Main 2021
Complex Numbers
Complex Numbers
Medium

Question

Let z and w be complex numbers such that z+iw=0\overline z + i\overline w = 0 and arg zw = π\pi . Then arg z equals :

Options

Solution

Key Concepts and Formulas

  • Complex Conjugate Properties: z=z\overline{\overline{z}} = z, z1+z2=z1+z2\overline{z_1 + z_2} = \overline{z_1} + \overline{z_2}, iz=iz\overline{iz} = -i\overline{z}
  • Argument Properties: arg(z1z2)=arg(z1)+arg(z2)\arg(z_1 z_2) = \arg(z_1) + \arg(z_2), arg(z1z2)=arg(z1)arg(z2)\arg(\frac{z_1}{z_2}) = \arg(z_1) - \arg(z_2), arg(zn)=narg(z)\arg(z^n) = n \arg(z)
  • Argument of i: arg(i)=π2\arg(i) = \frac{\pi}{2}

Step-by-Step Solution

1. Express z in terms of w using the given condition.

We are given z+iw=0\overline z + i\overline w = 0. Our goal is to isolate z\overline{z} and then eliminate the conjugates to find a direct relationship between zz and ww.

Isolating z\overline{z}, we have: z=iw\overline z = -i\overline w

Now, take the conjugate of both sides. This is done to eliminate the conjugate notation. z=iw\overline{\overline z} = \overline{-i\overline w}

Applying conjugate properties: z=iwz = \overline{-i} \cdot \overline{\overline{w}} z=iwz = i w

2. Express w in terms of z, then substitute into the second given equation.

From the previous step, we have z=iwz = iw. Solving for ww, we get: w=ziw = \frac{z}{i}

We are also given arg(zw)=π\arg(zw) = \pi. We want to substitute our expression for ww in terms of zz to get an equation involving only zz.

Substituting w=ziw = \frac{z}{i} into arg(zw)=π\arg(zw) = \pi, we get: arg(zzi)=π\arg\left(z \cdot \frac{z}{i}\right) = \pi arg(z2i)=π\arg\left(\frac{z^2}{i}\right) = \pi

3. Apply argument properties to simplify the equation.

We use the property arg(z1z2)=arg(z1)arg(z2)\arg(\frac{z_1}{z_2}) = \arg(z_1) - \arg(z_2): arg(z2)arg(i)=π\arg(z^2) - \arg(i) = \pi

Then, we use the property arg(zn)=narg(z)\arg(z^n) = n \arg(z): 2arg(z)arg(i)=π2\arg(z) - \arg(i) = \pi

4. Solve for arg(z).

We know that arg(i)=π2\arg(i) = \frac{\pi}{2}. Substituting this into the equation: 2arg(z)π2=π2\arg(z) - \frac{\pi}{2} = \pi

Adding π2\frac{\pi}{2} to both sides: 2arg(z)=π+π2=3π22\arg(z) = \pi + \frac{\pi}{2} = \frac{3\pi}{2}

Dividing both sides by 2: arg(z)=3π4\arg(z) = \frac{3\pi}{4}

Common Mistakes & Tips

  • Remember that i=i\overline{i} = -i. Failing to apply this correctly is a common source of error.
  • Be careful with the signs when applying argument properties, especially when dealing with division.
  • Always double-check your final answer to make sure it makes sense within the context of the problem.

Summary

By using the properties of complex conjugates and arguments, we were able to simplify the given equations and solve for arg(z)\arg(z). We first expressed zz in terms of ww and then substituted this into the second equation to eliminate ww. Then, using argument properties, we simplified and solved for arg(z)\arg(z). The final answer is 3π4\frac{3\pi}{4}.

Final Answer The final answer is 3π4\boxed{\frac{3\pi}{4}}, which corresponds to option (C).

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