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JEE Main 2019
Complex Numbers
Complex Numbers
Easy

Question

Let z 1 , z 2 be the roots of the equation z 2 + az + 12 = 0 and z 1 , z 2 form an equilateral triangle with origin. Then, the value of |a| is :

Answer: 1

Solution

Key Concepts and Formulas

  • Equilateral Triangle Condition (Complex Plane): If z1,z2,z3z_1, z_2, z_3 form an equilateral triangle, then z12+z22+z32=z1z2+z2z3+z3z1z_1^2 + z_2^2 + z_3^2 = z_1z_2 + z_2z_3 + z_3z_1. When one vertex is at the origin (z3=0z_3 = 0), this simplifies to z12+z22=z1z2z_1^2 + z_2^2 = z_1z_2, which can be further expressed as (z1+z2)2=3z1z2(z_1 + z_2)^2 = 3z_1z_2.
  • Vieta's Formulas: For a quadratic equation Ax2+Bx+C=0Ax^2 + Bx + C = 0, the sum of the roots is BA-\frac{B}{A} and the product of the roots is CA\frac{C}{A}.
  • Absolute Value: The absolute value of a number xx, denoted by x|x|, is its distance from zero. x=x|x| = x if x0x \geq 0, and x=x|x| = -x if x<0x < 0.

Step-by-Step Solution

Step 1: Apply the Equilateral Triangle Condition

Since z1,z2,z_1, z_2, and the origin (0) form an equilateral triangle, we can use the equilateral triangle condition with z3=0z_3 = 0: z12+z22+02=z1z2+z2(0)+0z1z_1^2 + z_2^2 + 0^2 = z_1z_2 + z_2(0) + 0z_1 This simplifies to: z12+z22=z1z2z_1^2 + z_2^2 = z_1z_2 To relate this to the sum and product of the roots, we rewrite the left side: (z1+z2)22z1z2=z1z2(z_1 + z_2)^2 - 2z_1z_2 = z_1z_2 Rearranging the terms, we get: (z1+z2)2=3z1z2(z_1 + z_2)^2 = 3z_1z_2 This equation relates the sum and product of the roots for this specific equilateral triangle configuration.

Step 2: Apply Vieta's Formulas

The given quadratic equation is z2+az+12=0z^2 + az + 12 = 0. Applying Vieta's formulas, we have:

  • Sum of the roots: z1+z2=a1=az_1 + z_2 = -\frac{a}{1} = -a
  • Product of the roots: z1z2=121=12z_1z_2 = \frac{12}{1} = 12 These formulas express the sum and product of the roots in terms of the coefficient 'a'.

Step 3: Substitute Vieta's Formulas into the Equilateral Triangle Condition

Substitute z1+z2=az_1 + z_2 = -a and z1z2=12z_1z_2 = 12 into the equation (z1+z2)2=3z1z2(z_1 + z_2)^2 = 3z_1z_2: (a)2=3(12)(-a)^2 = 3(12) a2=36a^2 = 36

Step 4: Solve for 'a'

Taking the square root of both sides: a=±36a = \pm \sqrt{36} a=±6a = \pm 6

Step 5: Find the Value of |a|

The question asks for the value of a|a|. a=±6|a| = |\pm 6| a=6|a| = 6

Common Mistakes & Tips

  • Sign Errors: Pay close attention to signs when applying Vieta's formulas, especially when identifying the coefficients A, B, and C.
  • Forgetting Absolute Value: Remember to take the absolute value at the end. If a=±xa = \pm x, the absolute value is a=x|a| = x.
  • Condition for Equilateral Triangle: Memorize the condition z12+z22+z32=z1z2+z2z3+z3z1z_1^2 + z_2^2 + z_3^2 = z_1z_2 + z_2z_3 + z_3z_1 or its equivalent forms, especially when one vertex is the origin.

Summary

We applied the condition for an equilateral triangle in the complex plane, using the origin as one of the vertices. We then used Vieta's formulas to relate the sum and product of the roots to the coefficient 'a' in the given quadratic equation. Substituting these into the equilateral triangle condition allowed us to solve for a2a^2 and subsequently find a|a|. The final answer is 6.

Final Answer The final answer is \boxed{6}.

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