Skip to main content
Back to Complex Numbers
JEE Main 2024
Complex Numbers
Complex Numbers
Easy

Question

For zCz \in \mathbb{C} if the minimum value of (z32+zp2i)(|z-3 \sqrt{2}|+|z-p \sqrt{2} i|) is 525 \sqrt{2}, then a value Question: of pp is _____________.

Options

Solution

Key Concepts and Formulas

  • Modulus as Distance: For complex numbers z1z_1 and z2z_2, z1z2|z_1 - z_2| represents the distance between the points corresponding to z1z_1 and z2z_2 in the complex plane.
  • Triangle Inequality: For complex numbers zz, z1z_1, and z2z_2, zz1+zz2z1z2|z - z_1| + |z - z_2| \ge |z_1 - z_2|. The minimum value of zz1+zz2|z - z_1| + |z - z_2| is z1z2|z_1 - z_2|, which occurs when zz lies on the line segment connecting z1z_1 and z2z_2.
  • Distance Formula: The distance between points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) in the Cartesian plane is (x2x1)2+(y2y1)2\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}.

Step-by-Step Solution

Step 1: Identify the complex numbers as points in the complex plane.

We are given the expression z32+zp2i|z - 3\sqrt{2}| + |z - p\sqrt{2}i|. This represents the sum of distances from a point zz in the complex plane to the points 323\sqrt{2} and p2ip\sqrt{2}i. Let z1=32z_1 = 3\sqrt{2} and z2=p2iz_2 = p\sqrt{2}i. In the complex plane, z1z_1 corresponds to the point (32,0)(3\sqrt{2}, 0) and z2z_2 corresponds to the point (0,p2)(0, p\sqrt{2}).

Step 2: Apply the triangle inequality to find the minimum value.

The minimum value of z32+zp2i|z - 3\sqrt{2}| + |z - p\sqrt{2}i| is the distance between the points 323\sqrt{2} and p2ip\sqrt{2}i. This minimum value is given as 525\sqrt{2}. Thus, we have 32p2i=52|3\sqrt{2} - p\sqrt{2}i| = 5\sqrt{2}

Step 3: Calculate the distance between the two points using the distance formula.

The distance between the points (32,0)(3\sqrt{2}, 0) and (0,p2)(0, p\sqrt{2}) is (032)2+(p20)2=(32)2+(p2)2=18+2p2\sqrt{(0 - 3\sqrt{2})^2 + (p\sqrt{2} - 0)^2} = \sqrt{(-3\sqrt{2})^2 + (p\sqrt{2})^2} = \sqrt{18 + 2p^2}

Step 4: Set up the equation and solve for p.

We are given that the minimum value is 525\sqrt{2}. Therefore, 18+2p2=52\sqrt{18 + 2p^2} = 5\sqrt{2} Squaring both sides, we get 18+2p2=(52)2=252=5018 + 2p^2 = (5\sqrt{2})^2 = 25 \cdot 2 = 50 2p2=5018=322p^2 = 50 - 18 = 32 p2=322=16p^2 = \frac{32}{2} = 16 p=±16=±4p = \pm \sqrt{16} = \pm 4

Step 5: Determine a value for p from the options.

Since the question asks for "a value of pp", we can choose either 44 or 4-4. The options provided include 4.

Common Mistakes & Tips

  • Forgetting the ±\pm sign: When taking the square root to solve for pp, remember to consider both positive and negative roots.
  • Misinterpreting Modulus: The expression za|z - a| represents the distance between the point zz and the point aa in the complex plane.
  • Squaring Square Roots: Be careful when squaring expressions involving square roots. Ensure that both the numerical and radical parts are squared correctly.

Summary

The problem involves finding a value of pp given the minimum distance between a complex number zz and two fixed points in the complex plane. By recognizing the geometric interpretation of the modulus and applying the distance formula, we set up an equation and solve for pp. We found that p=±4p = \pm 4, and the given options include p=4p=4.

Final Answer

The final answer is \boxed{4}, which corresponds to option (C).

Practice More Complex Numbers Questions

View All Questions