If α denotes the number of solutions of ∣1−i∣x=2x and β=(arg(z)∣z∣), where z=4π(1+i)4[π+i1−πi+1+πiπ−i],i=−1, then the distance of the point (α,β) from the line 4x−3y=7 is __________.
Answer: 2
Solution
Key Concepts and Formulas
Modulus of a Complex Number: For a complex number z=x+iy, its modulus is ∣z∣=x2+y2.
Argument of a Complex Number: The argument, arg(z), is the angle z makes with the positive real axis. For z=iy with y>0, arg(z)=2π.
Distance of a Point from a Line: The distance D of a point (x1,y1) from a line Ax+By+C=0 is D=A2+B2∣Ax1+By1+C∣.
Step-by-Step Solution
Part 1: Finding the value of α
Step 1: Calculate the modulus of 1−i
We need to find ∣1−i∣ to simplify the given equation.
∣1−i∣=12+(−1)2=2Explanation: We use the definition of the modulus of a complex number.
Step 2: Substitute and simplify the equation
Substitute ∣1−i∣=2 into the equation ∣1−i∣x=2x.
(2)x=2x
Rewrite 2 as 21/2:
(21/2)x=2x2x/2=2xExplanation: Expressing both sides with the same base allows us to compare exponents.
Step 3: Solve for x
Since the bases are equal, the exponents must be equal:
2x=xx=2xx−2x=0−x=0x=0
Therefore, α=1.
Explanation: Solving the equation for x gives the only solution.
Part 2: Finding the value of β
Step 1: Simplify (1+i)4
We simplify this term first to reduce the complexity of the expression for z.
(1+i)2=1+2i+i2=1+2i−1=2i(1+i)4=((1+i)2)2=(2i)2=4i2=−4Explanation: We use the binomial expansion and the property i2=−1.
Step 2: Simplify π+i1−πi+1+πiπ−i
We simplify each fraction separately and then add them.
π+i1−πi=(π+i)(π−i)(1−πi)(π−i)=π+1π−i−πi−π=π+1−i−πi=1+π−i(1+π)=−i1+πiπ−i=(1+πi)(1−πi)(π−i)(1−πi)=1+ππ−πi−i−π=1+π−i−πi=1+π−i(1+π)=−i
Therefore,
π+i1−πi+1+πiπ−i=−i+(−i)=−2iExplanation: We multiply the numerator and denominator of each fraction by the conjugate of the denominator to rationalize it.
Step 3: Simplify the expression for z
z=4π(1+i)4[π+i1−πi+1+πiπ−i]z=4π(−4)(−2i)=2πiExplanation: We substitute the simplified values from the previous steps.
Step 4: Calculate ∣z∣ and arg(z)
∣z∣=∣2πi∣=02+(2π)2=2πarg(z)=2πExplanation: We use the definitions of modulus and argument for a purely imaginary number.
Step 5: Calculate β
β=arg(z)∣z∣=2π2π=π2π⋅2=4Explanation: We substitute the values of ∣z∣ and arg(z) into the definition of β.
Part 3: Calculate the Distance
Step 1: State the point and the line equation
We have the point (α,β)=(1,4) and the line 4x−3y=7, which can be written as 4x−3y−7=0.
Step 2: Apply the distance formula
D=42+(−3)2∣4(1)−3(4)−7∣=16+9∣4−12−7∣=25∣−15∣=515=3Explanation: We substitute the values into the distance formula and calculate the result.
Common Mistakes & Tips
Careless arithmetic, especially with signs, can lead to errors. Double-check each calculation.
When simplifying complex fractions, multiplying by the conjugate is a reliable method.
Remember the correct formula for the distance between a point and a line.
Summary
By carefully simplifying the given expressions and applying the relevant formulas, we found that α=1, β=4, and the distance of the point (α,β) from the line 4x−3y=7 is 3. There seems to be an error in the question, as the correct distance is 3, not 2 as stated in the provided answer.