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JEE Main 2024
Complex Numbers
Complex Numbers
Easy

Question

If z=2+3iz=2+3 i, then z5+(zˉ)5z^{5}+(\bar{z})^{5} is equal to :

Options

Solution

Key Concepts and Formulas

  • Complex Conjugate: If z=a+biz = a + bi, where aa and bb are real numbers, then its complex conjugate is zˉ=abi\bar{z} = a - bi.
  • Conjugate of a Power: For any complex number zz and integer nn, zn=(zˉ)n\overline{z^n} = (\bar{z})^n.
  • Sum of a Complex Number and its Conjugate: z+zˉ=2Re(z)z + \bar{z} = 2\text{Re}(z), where Re(z)\text{Re}(z) denotes the real part of zz.

Step-by-Step Solution

1. Simplify the expression using conjugate properties

We are given the expression z5+(zˉ)5z^5 + (\bar{z})^5. Our goal is to simplify this expression using the properties of complex conjugates.

Using the property zn=(zˉ)n\overline{z^n} = (\bar{z})^n, we can rewrite (zˉ)5(\bar{z})^5 as z5\overline{z^5}. z5+(zˉ)5=z5+z5z^5 + (\bar{z})^5 = z^5 + \overline{z^5}

Now, using the property z+zˉ=2Re(z)z + \bar{z} = 2\text{Re}(z), we can rewrite the expression as: z5+z5=2Re(z5)z^5 + \overline{z^5} = 2\text{Re}(z^5)

Thus, we only need to find the real part of z5z^5 and multiply it by 2.

2. Calculate z2z^2

We are given z=2+3iz = 2 + 3i. We need to calculate z2z^2 to find higher powers of zz. z2=(2+3i)2z^2 = (2 + 3i)^2

Expanding the square: z2=(2)2+2(2)(3i)+(3i)2z^2 = (2)^2 + 2(2)(3i) + (3i)^2 z2=4+12i+9i2z^2 = 4 + 12i + 9i^2

Since i2=1i^2 = -1: z2=4+12i9z^2 = 4 + 12i - 9 z2=5+12iz^2 = -5 + 12i

3. Calculate z4z^4

Now, we calculate z4z^4 by squaring z2z^2: z4=(z2)2=(5+12i)2z^4 = (z^2)^2 = (-5 + 12i)^2

Expanding the square: z4=(5)2+2(5)(12i)+(12i)2z^4 = (-5)^2 + 2(-5)(12i) + (12i)^2 z4=25120i+144i2z^4 = 25 - 120i + 144i^2

Since i2=1i^2 = -1: z4=25120i144z^4 = 25 - 120i - 144 z4=119120iz^4 = -119 - 120i

4. Calculate z5z^5

Next, we calculate z5z^5 by multiplying z4z^4 and zz: z5=z4z=(119120i)(2+3i)z^5 = z^4 \cdot z = (-119 - 120i)(2 + 3i)

Expanding the product: z5=(119)(2)+(119)(3i)+(120i)(2)+(120i)(3i)z^5 = (-119)(2) + (-119)(3i) + (-120i)(2) + (-120i)(3i) z5=238357i240i360i2z^5 = -238 - 357i - 240i - 360i^2

Since i2=1i^2 = -1: z5=238357i240i+360z^5 = -238 - 357i - 240i + 360 z5=(238+360)+(357240)iz^5 = (-238 + 360) + (-357 - 240)i z5=122597iz^5 = 122 - 597i

5. Calculate 2Re(z5)2\text{Re}(z^5)

We have z5=122597iz^5 = 122 - 597i. Therefore, the real part of z5z^5 is: Re(z5)=122\text{Re}(z^5) = 122

Finally, we calculate 2Re(z5)2\text{Re}(z^5): 2Re(z5)=2(122)=2442\text{Re}(z^5) = 2(122) = 244

Common Mistakes & Tips

  • Sign Errors: Be extremely careful with signs when expanding and simplifying expressions involving complex numbers, especially when dealing with i2=1i^2 = -1.
  • Iterative Calculation: Break down higher powers into smaller, manageable steps to minimize errors.
  • Conjugate Properties: Remember to use the properties of conjugates to simplify the expressions, especially when dealing with sums and powers.

Summary

We used the properties of complex conjugates to simplify the expression z5+(zˉ)5z^5 + (\bar{z})^5 to 2Re(z5)2\text{Re}(z^5). We then calculated z5z^5 by iteratively finding z2z^2, z4z^4, and finally z5z^5. The real part of z5z^5 was found to be 122, and therefore, z5+(zˉ)5=2(122)=244z^5 + (\bar{z})^5 = 2(122) = 244.

The final answer is \boxed{244}, which corresponds to option (A).

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