Key Concepts and Formulas
- Complex Conjugate: If z=a+bi, where a and b are real numbers, then its complex conjugate is zˉ=a−bi.
- Conjugate of a Power: For any complex number z and integer n, zn=(zˉ)n.
- Sum of a Complex Number and its Conjugate: z+zˉ=2Re(z), where Re(z) denotes the real part of z.
Step-by-Step Solution
1. Simplify the expression using conjugate properties
We are given the expression z5+(zˉ)5. Our goal is to simplify this expression using the properties of complex conjugates.
Using the property zn=(zˉ)n, we can rewrite (zˉ)5 as z5.
z5+(zˉ)5=z5+z5
Now, using the property z+zˉ=2Re(z), we can rewrite the expression as:
z5+z5=2Re(z5)
Thus, we only need to find the real part of z5 and multiply it by 2.
2. Calculate z2
We are given z=2+3i. We need to calculate z2 to find higher powers of z.
z2=(2+3i)2
Expanding the square:
z2=(2)2+2(2)(3i)+(3i)2
z2=4+12i+9i2
Since i2=−1:
z2=4+12i−9
z2=−5+12i
3. Calculate z4
Now, we calculate z4 by squaring z2:
z4=(z2)2=(−5+12i)2
Expanding the square:
z4=(−5)2+2(−5)(12i)+(12i)2
z4=25−120i+144i2
Since i2=−1:
z4=25−120i−144
z4=−119−120i
4. Calculate z5
Next, we calculate z5 by multiplying z4 and z:
z5=z4⋅z=(−119−120i)(2+3i)
Expanding the product:
z5=(−119)(2)+(−119)(3i)+(−120i)(2)+(−120i)(3i)
z5=−238−357i−240i−360i2
Since i2=−1:
z5=−238−357i−240i+360
z5=(−238+360)+(−357−240)i
z5=122−597i
5. Calculate 2Re(z5)
We have z5=122−597i. Therefore, the real part of z5 is:
Re(z5)=122
Finally, we calculate 2Re(z5):
2Re(z5)=2(122)=244
Common Mistakes & Tips
- Sign Errors: Be extremely careful with signs when expanding and simplifying expressions involving complex numbers, especially when dealing with i2=−1.
- Iterative Calculation: Break down higher powers into smaller, manageable steps to minimize errors.
- Conjugate Properties: Remember to use the properties of conjugates to simplify the expressions, especially when dealing with sums and powers.
Summary
We used the properties of complex conjugates to simplify the expression z5+(zˉ)5 to 2Re(z5). We then calculated z5 by iteratively finding z2, z4, and finally z5. The real part of z5 was found to be 122, and therefore, z5+(zˉ)5=2(122)=244.
The final answer is \boxed{244}, which corresponds to option (A).