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JEE Main 2018
Complex Numbers
Complex Numbers
Easy

Question

If z=x+iyz=x+i y satisfies z2=0|z|-2=0 and ziz+5i=0|z-i|-|z+5 i|=0, then :

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Solution

Key Concepts and Formulas

  • Modulus of a Complex Number: For a complex number z=x+iyz = x + iy, the modulus is given by z=x2+y2|z| = \sqrt{x^2 + y^2}, representing the distance from the origin to the point (x,y)(x, y) in the complex plane.
  • Geometric Interpretation of zz0=r|z - z_0| = r: This equation represents a circle with center z0z_0 and radius rr in the complex plane.
  • Geometric Interpretation of zz1=zz2|z - z_1| = |z - z_2|: This equation represents the perpendicular bisector of the line segment joining the points representing the complex numbers z1z_1 and z2z_2 in the complex plane.

Step-by-Step Solution

Step 1: Analyze the first condition, z2=0|z| - 2 = 0

  • Explanation: This condition defines the modulus of the complex number zz. We will rewrite it to obtain an equation in terms of xx and yy.
  • Working: The given condition is: z2=0|z| - 2 = 0 Rearranging, we get: z=2|z| = 2 Substituting z=x+iyz = x + iy, we have: x2+y2=2\sqrt{x^2 + y^2} = 2 Squaring both sides, we obtain: x2+y2=4(Equation 1)x^2 + y^2 = 4 \quad \text{(Equation 1)}
  • Geometric Interpretation: This equation represents a circle centered at the origin (0,0)(0,0) with a radius of 22.

Step 2: Analyze the second condition, ziz+5i=0|z - i| - |z + 5i| = 0

  • Explanation: This condition equates the distances from zz to ii and from zz to 5i-5i. We'll rewrite it and interpret it geometrically.
  • Working: The given condition is: ziz+5i=0|z - i| - |z + 5i| = 0 Rearranging, we get: zi=z+5i|z - i| = |z + 5i| Rewriting z+5iz + 5i as z(5i)z - (-5i), we have: zi=z(5i)|z - i| = |z - (-5i)| Substituting z=x+iyz = x + iy, we get: x+iyi=x+iy+5i|x + iy - i| = |x + iy + 5i| x+i(y1)=x+i(y+5)|x + i(y - 1)| = |x + i(y + 5)| x2+(y1)2=x2+(y+5)2\sqrt{x^2 + (y - 1)^2} = \sqrt{x^2 + (y + 5)^2} Squaring both sides, we get: x2+(y1)2=x2+(y+5)2x^2 + (y - 1)^2 = x^2 + (y + 5)^2 x2+y22y+1=x2+y2+10y+25x^2 + y^2 - 2y + 1 = x^2 + y^2 + 10y + 25 Subtracting x2+y2x^2 + y^2 from both sides: 2y+1=10y+25-2y + 1 = 10y + 25 12y=24-12y = 24 y=2(Equation 2)y = -2 \quad \text{(Equation 2)}
  • Geometric Interpretation: This equation represents a horizontal line at y=2y = -2, which is the perpendicular bisector of the line segment joining (0,1)(0, 1) and (0,5)(0, -5).

Step 3: Combine both conditions to find xx and yy

  • Explanation: We will substitute the value of yy from Equation 2 into Equation 1 to find the value of xx.
  • Working: Substitute y=2y = -2 into x2+y2=4x^2 + y^2 = 4: x2+(2)2=4x^2 + (-2)^2 = 4 x2+4=4x^2 + 4 = 4 x2=0x^2 = 0 x=0x = 0 Thus, the complex number zz is 02i0 - 2i, so x=0x = 0 and y=2y = -2.

Step 4: Verify which option is correct

  • Explanation: We substitute x=0x=0 and y=2y=-2 into each of the options to find the correct equation.
  • Working:
    • (A) x+2y4=00+2(2)4=80x + 2y - 4 = 0 \Rightarrow 0 + 2(-2) - 4 = -8 \neq 0 (False)
    • (B) x2+y4=002+(2)4=60x^2 + y - 4 = 0 \Rightarrow 0^2 + (-2) - 4 = -6 \neq 0 (False)
    • (C) x+2y+4=00+2(2)+4=4+4=0x + 2y + 4 = 0 \Rightarrow 0 + 2(-2) + 4 = -4 + 4 = 0 (True)
    • (D) x2y+3=002(2)+3=50x^2 - y + 3 = 0 \Rightarrow 0^2 - (-2) + 3 = 5 \neq 0 (False)

Common Mistakes & Tips

  • Sign Errors: Be especially careful with signs when substituting and simplifying equations, particularly when dealing with z+5iz+5i which should be treated as z(5i)z - (-5i).
  • Geometric Visualization: Visualizing the complex numbers and their relationships geometrically can greatly simplify the problem and provide valuable intuition.
  • Verification: Always verify your final solution by substituting the obtained values back into the original equations and the answer options.

Summary

By interpreting the given conditions geometrically, we found that z=2|z| = 2 represents a circle centered at the origin with radius 2, and zi=z+5i|z - i| = |z + 5i| represents the perpendicular bisector of the line segment joining ii and 5i-5i, which simplifies to the line y=2y = -2. Solving these equations simultaneously gave us x=0x = 0 and y=2y = -2. Substituting these values into the options, we found that the correct equation is x+2y+4=0x + 2y + 4 = 0.

The final answer is \boxed{x+2y+4=0}, which corresponds to option (C).

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