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JEE Main 2021
Complex Numbers
Complex Numbers
Easy

Question

Let α\alpha and β\beta be the roots of the equation x 2 + (2i - 1) = 0. Then, the value of |α\alpha 8 + β\beta 8 | is equal to :

Options

Solution

Key Concepts and Formulas

  • Roots of a Quadratic Equation: If α\alpha is a root of the equation ax2+bx+c=0ax^2 + bx + c = 0, then aα2+bα+c=0a\alpha^2 + b\alpha + c = 0.
  • Modulus of a Complex Number: For a complex number z=a+biz = a + bi, its modulus is given by z=a2+b2|z| = \sqrt{a^2 + b^2}.
  • Properties of Modulus: zn=zn|z^n| = |z|^n and kz=kz|kz| = |k||z| for any integer nn and real number kk.

Step-by-Step Solution

Step 1: Analyze the Given Equation and its Roots

We are given the quadratic equation: x2+(2i1)=0x^2 + (2i - 1) = 0 We can rewrite this as x2=12ix^2 = 1 - 2i Since α\alpha and β\beta are the roots of the equation, they must satisfy the equation. Therefore, α2=12i\alpha^2 = 1 - 2i and β2=12i\beta^2 = 1 - 2i This tells us that α2=β2\alpha^2 = \beta^2. This is a crucial relationship that will simplify our calculations.

Step 2: Calculate the Modulus of α2\alpha^2 (or β2\beta^2)

Since α2=12i\alpha^2 = 1 - 2i, we can find its modulus. Let z=12iz = 1 - 2i. Then the real part is a=1a = 1 and the imaginary part is b=2b = -2. Using the formula for the modulus of a complex number, z=a2+b2|z| = \sqrt{a^2 + b^2}: α2=12i=(1)2+(2)2|\alpha^2| = |1 - 2i| = \sqrt{(1)^2 + (-2)^2} α2=1+4|\alpha^2| = \sqrt{1 + 4} α2=5|\alpha^2| = \sqrt{5} Since α2=β2\alpha^2 = \beta^2, we also have β2=5|\beta^2| = \sqrt{5}.

Step 3: Simplify the Expression α8+β8|\alpha^8 + \beta^8|

We want to find the value of α8+β8|\alpha^8 + \beta^8|. Since α2=β2\alpha^2 = \beta^2, we have (α2)4=(β2)4(\alpha^2)^4 = (\beta^2)^4, which means α8=β8\alpha^8 = \beta^8 Now, substitute β8\beta^8 with α8\alpha^8 in the expression: α8+β8=α8+α8|\alpha^8 + \beta^8| = |\alpha^8 + \alpha^8| α8+β8=2α8|\alpha^8 + \beta^8| = |2\alpha^8| Using the modulus property kz=kz|kz| = |k||z|, where k=2k=2: 2α8=2α8|2\alpha^8| = 2|\alpha^8| Using the modulus property zn=zn|z^n| = |z|^n, we can write α8|\alpha^8| as (α2)4|(\alpha^2)^4| and then as α24|\alpha^2|^4: 2α8=2(α2)42|\alpha^8| = 2|(\alpha^2)^4| 2(α2)4=2α242|(\alpha^2)^4| = 2|\alpha^2|^4

Step 4: Substitute and Compute the Final Result

From Step 2, we found that α2=5|\alpha^2| = \sqrt{5}. Substituting this value into our simplified expression: 2α24=2(5)42|\alpha^2|^4 = 2(\sqrt{5})^4 To compute (5)4(\sqrt{5})^4: (5)4=(51/2)4(\sqrt{5})^4 = (5^{1/2})^4 =5(1/2)×4 = 5^{(1/2) \times 4} =52 = 5^2 =25 = 25 Finally, multiply by 2: 2×25=502 \times 25 = 50 Thus, the value of α8+β8|\alpha^8 + \beta^8| is 5050.

Common Mistakes & Tips

  • Avoid Explicit Root Calculation: Avoid the unnecessary step of finding the exact values of α\alpha and β\beta. Instead, utilize the properties of roots and moduli.
  • Correct Modulus Calculation: Ensure correct calculation of the modulus. a+bi=a2+b2|a+bi| = \sqrt{a^2+b^2} is the correct formula.
  • Use Modulus Properties: Remember and apply the properties of modulus, such as zn=zn|z^n| = |z|^n and kz=kz|kz| = |k||z|.

Summary

This problem demonstrates the power of using properties of complex numbers and the definition of roots to simplify calculations. The key insight was recognizing that α2=β2\alpha^2 = \beta^2, which significantly simplified the expression α8+β8|\alpha^8 + \beta^8| and eliminated the need to find the actual complex roots. The final answer is 50.

Final Answer The final answer is 50\boxed{50}, which corresponds to option (A).

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