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JEE Main 2024
Complex Numbers
Complex Numbers
Easy

Question

Let z1=2+3i\mathrm{z_1=2+3i} and z2=3+4i\mathrm{z_2=3+4i}. The set S={zC:zz12zz22=z1z22}\mathrm{S = \left\{ {z \in \mathbb{C}:{{\left| {z - {z_1}} \right|}^2} - {{\left| {z - {z_2}} \right|}^2} = {{\left| {{z_1} - {z_2}} \right|}^2}} \right\}} represents a

Options

Solution

Key Concepts and Formulas

  • Distance in the Complex Plane: For complex numbers z=x+iyz = x+iy and z0=x0+iy0z_0 = x_0 + iy_0, the distance between them is zz0=(xx0)2+(yy0)2|z - z_0| = \sqrt{(x-x_0)^2 + (y-y_0)^2}. Thus, zz02=(xx0)2+(yy0)2|z-z_0|^2 = (x-x_0)^2 + (y-y_0)^2.
  • Equation of a Straight Line: A linear equation of the form ax+by=cax + by = c represents a straight line in the Cartesian plane.
  • Intercepts of a Straight Line: The x-intercept is the point where the line crosses the x-axis (y=0), and the y-intercept is the point where the line crosses the y-axis (x=0).

Step-by-Step Solution

Step 1: Represent Complex Numbers in Cartesian Coordinates

We represent the complex numbers as points in the Cartesian plane. Let z=x+iyz = x + iy, where xx and yy are real numbers. We are given z1=2+3iz_1 = 2 + 3i and z2=3+4iz_2 = 3 + 4i. These correspond to the points (2,3)(2, 3) and (3,4)(3, 4) respectively.

Step 2: Calculate the Squared Moduli (Squared Distances)

We calculate the squared moduli required for the given equation.

  • Calculating zz12|z - z_1|^2: zz1=(x+iy)(2+3i)=(x2)+i(y3)z - z_1 = (x + iy) - (2 + 3i) = (x - 2) + i(y - 3) Therefore, zz12=(x2)2+(y3)2|z - z_1|^2 = (x - 2)^2 + (y - 3)^2.

  • Calculating zz22|z - z_2|^2: zz2=(x+iy)(3+4i)=(x3)+i(y4)z - z_2 = (x + iy) - (3 + 4i) = (x - 3) + i(y - 4) Therefore, zz22=(x3)2+(y4)2|z - z_2|^2 = (x - 3)^2 + (y - 4)^2.

  • Calculating z1z22|z_1 - z_2|^2: z1z2=(2+3i)(3+4i)=1iz_1 - z_2 = (2 + 3i) - (3 + 4i) = -1 - i Therefore, z1z22=(1)2+(1)2=1+1=2|z_1 - z_2|^2 = (-1)^2 + (-1)^2 = 1 + 1 = 2.

Step 3: Substitute and Simplify the Equation

Substitute the expressions for the squared moduli into the given equation: zz12zz22=z1z22|z - z_1|^2 - |z - z_2|^2 = |z_1 - z_2|^2 (x2)2+(y3)2[(x3)2+(y4)2]=2(x - 2)^2 + (y - 3)^2 - [(x - 3)^2 + (y - 4)^2] = 2 Expand the squared terms: (x24x+4)+(y26y+9)(x26x+9)(y28y+16)=2(x^2 - 4x + 4) + (y^2 - 6y + 9) - (x^2 - 6x + 9) - (y^2 - 8y + 16) = 2 Distribute the negative sign: x24x+4+y26y+9x2+6x9y2+8y16=2x^2 - 4x + 4 + y^2 - 6y + 9 - x^2 + 6x - 9 - y^2 + 8y - 16 = 2 Combine like terms: (x2x2)+(y2y2)+(4x+6x)+(6y+8y)+(4+9916)=2(x^2 - x^2) + (y^2 - y^2) + (-4x + 6x) + (-6y + 8y) + (4 + 9 - 9 - 16) = 2 0+0+2x+2y12=20 + 0 + 2x + 2y - 12 = 2 2x+2y12=22x + 2y - 12 = 2

Step 4: Determine the Locus

Simplify the equation to find the locus: 2x+2y=2+122x + 2y = 2 + 12 2x+2y=142x + 2y = 14 Divide by 2: x+y=7x + y = 7 This equation represents a straight line.

Step 5: Calculate the Intercepts and their Sum

  • x-intercept: Set y=0y = 0: x+0=7    x=7x + 0 = 7 \implies x = 7
  • y-intercept: Set x=0x = 0: 0+y=7    y=70 + y = 7 \implies y = 7 The sum of the intercepts is 7+7=147 + 7 = 14.

Interpretation and Evaluation of Options

The equation x+y=7x+y=7 represents a straight line. The sum of its intercepts is 14. This corresponds to option (D).

Common Mistakes & Tips

  • Sign Errors: Be extremely careful when distributing the negative sign in Step 3. This is a common source of errors.
  • Expanding Squares: Ensure you expand the squared terms correctly using the formula (ab)2=a22ab+b2(a-b)^2 = a^2 - 2ab + b^2.
  • Simplify Carefully: Double-check each step of simplification to avoid mistakes in combining like terms.

Summary

The given equation simplifies to x+y=7x+y=7, which represents a straight line. The x and y intercepts are both 7, so their sum is 14. Therefore, the set SS represents a straight line with the sum of its intercepts on the coordinate axes equal to 14.

Final Answer The final answer is \boxed{14}, which corresponds to option (D).

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