Skip to main content
Back to Complex Numbers
JEE Main 2023
Complex Numbers
Complex Numbers
Hard

Question

Let the curve z(1+i)+zˉ(1i)=4,zCz(1+i)+\bar{z}(1-i)=4, z \in C, divide the region z31|z-3| \leq 1 into two parts of areas α\alpha and β\beta. Then αβ|\alpha-\beta| equals :

Options

Solution

Key Concepts and Formulas

  • Complex Numbers and their Geometric Representation: A complex number z=x+iyz = x+iy can be represented as a point (x,y)(x,y) in the complex plane. The modulus zc|z-c| represents the distance between zz and cc.
  • Equation of a Line: The equation Ax+By+C=0Ax + By + C = 0 represents a straight line in the Cartesian plane.
  • Distance from a Point to a Line: The distance DD from a point (x0,y0)(x_0, y_0) to a line Ax+By+C=0Ax+By+C=0 is given by D=Ax0+By0+CA2+B2D = \frac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}.
  • Area of a Circular Segment: The area of a circular segment is given by A=12R2(θsinθ)A = \frac{1}{2}R^2(\theta - \sin\theta), where RR is the radius of the circle and θ\theta is the central angle in radians.

Step-by-Step Solution

Step 1: Convert the complex equation of the curve to Cartesian form.

  • Purpose: Convert the complex equation z(1+i)+zˉ(1i)=4z(1+i)+\bar{z}(1-i)=4 into its Cartesian form to identify the line.
  • Method: Substitute z=x+iyz = x+iy and zˉ=xiy\bar{z} = x-iy into the equation.
  • Detailed Working: z(1+i)+zˉ(1i)=4z(1+i)+\bar{z}(1-i)=4 (x+iy)(1+i)+(xiy)(1i)=4(x+iy)(1+i)+(x-iy)(1-i)=4 x+ix+iyy+xixiyy=4x+ix+iy-y+x-ix-iy-y=4 2x2y=42x-2y=4 xy=2x-y=2
  • Explanation: The equation xy=2x-y=2 represents a straight line in the Cartesian plane.

Step 2: Convert the complex inequality of the region to Cartesian form.

  • Purpose: Convert the complex inequality z31|z-3| \leq 1 to its Cartesian form to identify the region.
  • Method: Substitute z=x+iyz = x+iy into the inequality.
  • Detailed Working: z31|z-3| \leq 1 (x+iy)31|(x+iy)-3| \leq 1 (x3)+iy1|(x-3)+iy| \leq 1 (x3)2+y21\sqrt{(x-3)^2+y^2} \leq 1 (x3)2+y21(x-3)^2+y^2 \leq 1
  • Explanation: The inequality (x3)2+y21(x-3)^2+y^2 \leq 1 represents a closed circular disk centered at (3,0)(3,0) with radius 11.

Step 3: Determine how the line divides the circular region.

  • Purpose: Calculate the areas α\alpha and β\beta of the two parts into which the line xy=2x-y=2 divides the circular disk (x3)2+y21(x-3)^2+y^2 \leq 1.

  • Method: Find the distance from the center of the circle to the line, and use this to find the central angle. Then, use the formula for the area of a circular segment.

  • Detailed Working:

    1. Distance from the center of the circle to the line: The center of the circle is C(3,0)C(3,0) and the line is xy2=0x-y-2=0. D=1(3)+(1)(0)212+(1)2=322=12D = \frac{|1(3)+(-1)(0)-2|}{\sqrt{1^2+(-1)^2}} = \frac{|3-2|}{\sqrt{2}} = \frac{1}{\sqrt{2}}
    2. Central angle subtended by the chord: cos(θ/2)=DR=1/21=12\cos(\theta/2) = \frac{D}{R} = \frac{1/\sqrt{2}}{1} = \frac{1}{\sqrt{2}} θ/2=π4\theta/2 = \frac{\pi}{4} θ=π2\theta = \frac{\pi}{2}
    3. Areas of the circular segments: Acircle=πR2=π(1)2=πA_{\text{circle}} = \pi R^2 = \pi (1)^2 = \pi The area of the circular segment is A=12R2(θsinθ)=12(1)2(π2sinπ2)=12(π21)=π412A = \frac{1}{2}R^2(\theta - \sin\theta) = \frac{1}{2}(1)^2(\frac{\pi}{2} - \sin\frac{\pi}{2}) = \frac{1}{2}(\frac{\pi}{2} - 1) = \frac{\pi}{4} - \frac{1}{2}. So, α=π412\alpha = \frac{\pi}{4} - \frac{1}{2}. Then β=πα=π(π412)=3π4+12\beta = \pi - \alpha = \pi - (\frac{\pi}{4} - \frac{1}{2}) = \frac{3\pi}{4} + \frac{1}{2}.
  • Explanation: The distance from the center to the line is less than the radius, so the line intersects the circle. The central angle is π/2\pi/2, which allows us to calculate the area of the smaller segment α\alpha using the formula for the area of a segment, and the area of the larger segment β\beta by subtracting α\alpha from the total area of the circle.

Step 4: Calculate the absolute difference of the areas.

  • Purpose: Calculate αβ|\alpha-\beta|.

  • Method: Substitute the values of α\alpha and β\beta obtained in the previous step.

  • Detailed Working: αβ=(π412)(3π4+12)|\alpha - \beta| = \left|\left(\frac{\pi}{4} - \frac{1}{2}\right) - \left(\frac{3\pi}{4} + \frac{1}{2}\right)\right| =π4123π412= \left|\frac{\pi}{4} - \frac{1}{2} - \frac{3\pi}{4} - \frac{1}{2}\right| =π21= \left|-\frac{\pi}{2} - 1\right| =π22=π+22=1+π2= \left|\frac{-\pi - 2}{2}\right| = \frac{\pi+2}{2} = 1 + \frac{\pi}{2}

  • Explanation: The absolute difference between the two areas is calculated by subtracting the smaller area from the larger area and taking the absolute value.

Step 5: Find the Error in the Provided Answer

  • Purpose: Identify the error in the provided answer, which claims the answer is 1+π31 + \frac{\pi}{3}.
  • Method: Review all steps and identify inconsistencies.
  • Detailed Working: The correct answer is 1+π21 + \frac{\pi}{2}. The provided options are (A) 1+π31+\frac{\pi}{3}, (B) 1+π61+\frac{\pi}{6}, (C) 1+π21+\frac{\pi}{2}, (D) 1+π41+\frac{\pi}{4}. Our answer matches option (C). The original "Correct Answer" marking (A) is incorrect.

Common Mistakes & Tips

  • Sign Errors: Be very careful with signs when expanding expressions and substituting values.
  • Radian Mode: Ensure your calculator is in radian mode when evaluating trigonometric functions with angles in radians.
  • Geometric Intuition: Always try to visualize the problem geometrically. This can help you catch errors and understand the relationships between different quantities.

Summary

We converted the complex equation and inequality into Cartesian form, identified the line and circle, calculated the distance from the center to the line, found the central angle, and computed the areas of the two segments. The absolute difference between the areas is 1+π21 + \frac{\pi}{2}.

The final answer is \boxed{1+\frac{\pi}{2}}, which corresponds to option (C).

Practice More Complex Numbers Questions

View All Questions