Let the minimum value v0 of v=∣z∣2+∣z−3∣2+∣z−6i∣2,z∈C is attained at z=z0. Then 2z02−zˉ03+32+v02 is equal to :
Options
Solution
Key Concepts and Formulas
Modulus of a Complex Number: If z=x+iy, where x and y are real numbers, then ∣z∣=x2+y2, and ∣z∣2=x2+y2.
Completing the Square: The method of completing the square transforms a quadratic expression of the form ax2+bx+c into a(x−h)2+k, where h=−2ab and k=c−4ab2.
Centroid of Complex Numbers: The centroid of complex numbers z1,z2,…,zn is given by z=nz1+z2+⋯+zn. The sum ∑k=1n∣z−zk∣2 is minimized when z is the centroid.
Step-by-Step Solution
Step 1: Convert to Cartesian Coordinates
We are given v=∣z∣2+∣z−3∣2+∣z−6i∣2. To work with this algebraically, we express z in Cartesian form:
Let z=x+iy, where x and y are real numbers. This allows us to express the modulus in terms of x and y.
Now we expand each term:
∣z∣2=∣x+iy∣2=x2+y2
∣z−3∣2=∣(x−3)+iy∣2=(x−3)2+y2=x2−6x+9+y2
∣z−6i∣2=∣x+i(y−6)∣2=x2+(y−6)2=x2+y2−12y+36
Step 2: Expand and Simplify the Expression for v
Substitute these expanded forms back into the expression for v:
v=(x2+y2)+(x2−6x+9+y2)+(x2+y2−12y+36)
Combine like terms:
v=3x2+3y2−6x−12y+45
Step 3: Complete the Square to Find the Minimum Value
We complete the square for the x and y terms to find the minimum value. First, factor out the coefficient 3:
v=3(x2−2x)+3(y2−4y)+45
Complete the square for x2−2x:
x2−2x=(x−1)2−1
Complete the square for y2−4y:
y2−4y=(y−2)2−4
Substitute these back into the expression for v:
v=3((x−1)2−1)+3((y−2)2−4)+45v=3(x−1)2−3+3(y−2)2−12+45v=3(x−1)2+3(y−2)2+30
Step 4: Determine the Minimum Value (v0) and the Complex Number (z0) where it's attained
Since (x−1)2≥0 and (y−2)2≥0, the minimum value of v occurs when x=1 and y=2.
Thus, z0=x+iy=1+2i.
The minimum value is v0=3(0)+3(0)+30=30.
Step 5: Calculate the Final Expression 2z02−zˉ03+32+v02
Calculate the final expression:
∣2z02−zˉ03+3∣2+v02=100+900=1000
Common Mistakes & Tips
Be careful with signs when expanding and simplifying complex expressions. A common mistake is to incorrectly calculate powers of i.
Remember that the minimum value of a sum of squared distances is attained at the centroid of the points.
Double-check your arithmetic when calculating z02 and zˉ03.
Summary
We converted the complex numbers to Cartesian coordinates, completed the square to find the minimum value v0=30, and the point where it occurs z0=1+2i. Then we computed ∣2z02−zˉ03+3∣2+v02=1000.
The final answer is \boxed{1000}, which corresponds to option (A).