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JEE Main 2024
Complex Numbers
Complex Numbers
Medium

Question

Let zz be a complex number such that z=1|z|=1. If 2+k2zk+zˉ=kz,kR\frac{2+\mathrm{k}^2 z}{\mathrm{k}+\bar{z}}=\mathrm{k} z, \mathrm{k} \in \mathbf{R}, then the maximum distance of k+ik2\mathrm{k}+i \mathrm{k}^2 from the circle z(1+2i)=1|z-(1+2 i)|=1 is :

Options

Solution

1. Key Concepts and Formulas

  • Modulus Property for Unit Circle: If z=1|z| = 1, then zzˉ=z2=1z\bar{z} = |z|^2 = 1.
  • Distance between Complex Numbers: The distance between z1z_1 and z2z_2 is z1z2|z_1 - z_2|.
  • Equation of a Circle in Complex Plane: zz0=R|z - z_0| = R represents a circle with center z0z_0 and radius RR.
  • Maximum Distance from a Point to a Circle: If PP is a point outside the circle with center CC and radius RR, the maximum distance from PP to the circle is PC+R|P - C| + R.

2. Step-by-Step Solution

Step 1: Eliminate the Denominator We are given 2+k2zk+zˉ=kz\frac{2+k^2 z}{k+\bar{z}} = kz. To simplify, we multiply both sides by the denominator: 2+k2z=kz(k+zˉ)2 + k^2 z = kz(k + \bar{z})

  • Why this step? This is a standard algebraic technique to remove the fraction and make the equation easier to work with.

Step 2: Distribute and Simplify Expanding the right side, we get: 2+k2z=k2z+kzzˉ2 + k^2 z = k^2 z + k z \bar{z}

  • Why this step? Expanding the expression allows us to isolate and simplify terms involving zz and zˉ\bar{z}.

Step 3: Use the Modulus Property Since z=1|z| = 1, we know zzˉ=1z\bar{z} = 1. Substituting this into the equation: 2+k2z=k2z+k(1)2 + k^2 z = k^2 z + k(1) 2+k2z=k2z+k2 + k^2 z = k^2 z + k

  • Why this step? This crucial step uses the given information z=1|z|=1 to eliminate the product zzˉz\bar{z}, which simplifies the equation significantly and allows us to solve for kk.

Step 4: Solve for k Subtracting k2zk^2 z from both sides, we have: 2=k2 = k

  • Why this step? This isolates kk, giving us its value directly.

Step 5: Determine the Point P We need to find the maximum distance of k+ik2k + ik^2 from the circle. Since k=2k=2: P=k+ik2=2+i(22)=2+4iP = k + ik^2 = 2 + i(2^2) = 2 + 4i This corresponds to the point (2,4)(2,4) in the complex plane.

  • Why this step? We substitute the value of kk we found to determine the exact location of the point PP in the complex plane.

Step 6: Identify the Circle's Center and Radius The equation of the circle is z(1+2i)=1|z - (1 + 2i)| = 1. This is in the form zz0=R|z - z_0| = R, so:

  • Center: C=1+2iC = 1 + 2i (or the point (1,2)(1,2))
  • Radius: R=1R = 1
  • Why this step? Identifying the center and radius of the circle is essential for calculating the distance from point PP to the circle.

Step 7: Calculate the Distance from P to C We find the distance between P=2+4iP = 2 + 4i and C=1+2iC = 1 + 2i: PC=(2+4i)(1+2i)=1+2i|P - C| = |(2 + 4i) - (1 + 2i)| = |1 + 2i| 1+2i=12+22=1+4=5|1 + 2i| = \sqrt{1^2 + 2^2} = \sqrt{1 + 4} = \sqrt{5}

  • Why this step? This calculates the distance between the point PP and the center of the circle, which is needed to find the maximum distance.

Step 8: Calculate the Maximum Distance The maximum distance is the distance from PP to CC plus the radius RR: Maximum Distance=PC+R=5+1\text{Maximum Distance} = |P - C| + R = \sqrt{5} + 1

  • Why this step? This applies the geometric principle that the maximum distance from a point to a circle is the distance to the center plus the radius.

3. Common Mistakes & Tips

  • Forgetting that z=1|z| = 1 implies zzˉ=1z\bar{z} = 1 and not using it to simplify the equation.
  • Misidentifying the center or radius of the circle from its equation.
  • Calculating the distance to the center but forgetting to add the radius to find the maximum distance.

4. Summary

We started with the given equation and the condition z=1|z|=1. We used the property zzˉ=1z\bar{z}=1 to simplify the equation and solve for kk. Then, we substituted kk into the expression for the external point PP. Finally, we found the distance between PP and the center of the circle and added the radius to find the maximum distance, which is 5+1\sqrt{5} + 1.

5. Final Answer

The final answer is 5+1\boxed{\sqrt{5}+1}, which corresponds to option (A).

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