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JEE Main 2019
Complex Numbers
Complex Numbers
Easy

Question

The point represented by 2 + i in the Argand plane moves 1 unit eastwards, then 2 units northwards and finally from there 222\sqrt 2 units in the south-westwardsdirection. Then its new position in the Argand plane is at the point represented by :

Options

Solution

Key Concepts and Formulas

  • Complex Number Representation: A complex number z=x+iyz = x + iy represents a point (x,y)(x, y) in the Argand plane.
  • Translation as Complex Addition: Translating a point represented by z1z_1 by a displacement represented by z2z_2 results in a new position z1+z2z_1 + z_2.
  • Polar Form: A complex number can be represented in polar form as z=r(cosθ+isinθ)z = r(\cos\theta + i\sin\theta), where rr is the magnitude and θ\theta is the angle with respect to the positive real axis.

Step-by-Step Solution

Step 1: Initial Position

The point starts at 2+i2 + i.

  • Why this step: This establishes the initial complex number representing the point's starting location in the Argand plane. Z0=2+iZ_0 = 2 + i

Step 2: Movement 1 unit Eastwards

The point moves 1 unit eastwards.

  • Why this step: Moving eastwards corresponds to adding a real number to the complex number. Z1=Z0+1Z_1 = Z_0 + 1 Z1=(2+i)+1Z_1 = (2 + i) + 1 Z1=3+iZ_1 = 3 + i

Step 3: Movement 2 units Northwards

The point moves 2 units northwards.

  • Why this step: Moving northwards corresponds to adding a positive imaginary number to the complex number. Z2=Z1+2iZ_2 = Z_1 + 2i Z2=(3+i)+2iZ_2 = (3 + i) + 2i Z2=3+3iZ_2 = 3 + 3i

Step 4: Movement 222\sqrt{2} units South-westwards

The point moves 222\sqrt{2} units in the south-west direction.

  • Why this step: South-west corresponds to an angle of 225225^\circ or 135-135^\circ from the positive real axis. We need to find the complex number that represents this displacement and add it to the current position.
  • Find the angle: The angle is 135-135^\circ.
  • Calculate trigonometric values: cos(135)=22=12\cos(-135^\circ) = -\frac{\sqrt{2}}{2} = -\frac{1}{\sqrt{2}} sin(135)=22=12\sin(-135^\circ) = -\frac{\sqrt{2}}{2} = -\frac{1}{\sqrt{2}}
  • Construct the displacement complex number (ΔZ3\Delta Z_3): ΔZ3=22(cos(135)+isin(135))\Delta Z_3 = 2\sqrt{2} \left( \cos(-135^\circ) + i\sin(-135^\circ) \right) ΔZ3=22(12i12)\Delta Z_3 = 2\sqrt{2} \left( -\frac{1}{\sqrt{2}} - i\frac{1}{\sqrt{2}} \right) ΔZ3=22i\Delta Z_3 = -2 - 2i
  • Add the displacement to the current position: ZF=Z2+ΔZ3Z_F = Z_2 + \Delta Z_3 ZF=(3+3i)+(22i)Z_F = (3 + 3i) + (-2 - 2i) ZF=1+iZ_F = 1 + i

Common Mistakes & Tips

  • Direction and Angles: Always measure angles counter-clockwise from the positive real axis. Be especially careful with signs in different quadrants.
  • Complex Addition: Make sure to add the real parts together and the imaginary parts together separately.

Summary

The problem involves a series of translations in the Argand plane, which can be easily solved by representing the point's position and each translation as complex numbers and then adding them. After moving 1 unit east, 2 units north, and 222\sqrt{2} units south-west, the final position of the point is 1+i1 + i.

The final answer is \boxed{1 + i}, which corresponds to option (B).

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