Skip to main content
Back to Conic Sections
JEE Main 2018
Conic Sections
Ellipse
Easy

Question

An ellipse has OBOB as semi minor axis, FF and FF' its focii and theangle FBFFBF' is a right angle. Then the eccentricity of the ellipse is :

Options

Solution

1. Understanding the Ellipse and its Parameters

To solve this problem, we must first recall the fundamental properties and definitions of an ellipse.

  • Standard Equation: We typically consider an ellipse centered at the origin (0,0)(0,0) with its major axis along the x-axis. Its standard equation is: x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 Here, aa represents the length of the semi-major axis (half the length of the major axis), and bb represents the length of the semi-minor axis (half the length of the minor axis). For an ellipse, it is always true that a>b>0a > b > 0.

  • Foci: The foci are two fixed points inside the ellipse, conventionally denoted by FF and FF'. Their coordinates are F(ae,0)F(ae, 0) and F(ae,0)F'(-ae, 0), where

Practice More Conic Sections Questions

View All Questions