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JEE Main 2019
Conic Sections
Hyperbola
Medium

Question

For the Hyperbola x2cos2αy2sin2α=1{{{x^2}} \over {{{\cos }^2}\alpha }} - {{{y^2}} \over {{{\sin }^2}\alpha }} = 1 , which of the following remains constant when α\alpha varies==?

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Solution

Key Concept: The Standard Equation of a Hyperbola and its Features

A hyperbola centered at the origin, with its transverse axis lying along the x-axis (meaning its foci and vertices are on the x-axis), has the standard equation: x2a2y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 Here, aa and bb are positive real numbers representing the lengths of the semi-transverse and semi-conjugate axes, respectively. From this standard form, we can define its key features:

  • Semi-transverse axis (aa): The distance from the center to a vertex.
  • Vertices: Located at $(\pm a,

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