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JEE Main 2023
Conic Sections
Parabola
Hard

Question

Let rr be the radius of the circle, which touches xx - axis at point (a,0),a<0(a, 0), a<0 and the parabola y2=9x\mathrm{y}^2=9 x at the point (4,6)(4,6). Then rr is equal to ______.

Answer: 2

Solution

This problem involves a circle tangent to both the x-axis and a parabola. The core idea is to use the geometric properties of tangency to establish relationships between the circle's parameters (center and radius) and the given points/curves.

1. Key Concepts and Formulas

  • Equation of a Circle: A circle with center (h,k)(h,k) and radius rr has the equation (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2.
  • Circle Tangent to x-axis: If a circle touches the x-axis at (a,0)(a,0), its center must be (a,±r)(a, \pm r), where rr is the radius. Since the point of tangency with the parabola (4,6)(4,6) has a positive

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