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JEE Main 2020
Conic Sections
Parabola
Easy

Question

P and Q are two distinct points on the parabola, y 2 = 4x, with parameters t and t 1 respectively. If the normal at P passes through Q, then the minimum value of t12t_1^2 is :

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Solution

Here's a detailed, step-by-step solution designed to be clear, elaborate, and educational, addressing the problem and the discrepancy in the provided answer.


1. Understanding the Parabola and Parametric Form

The given equation of the parabola is y2=4xy^2 = 4x. This is a standard form parabola y2=4axy^2 = 4ax, where we can identify a=1a=1.

For a parabola y2=4axy^2 = 4ax, the parametric coordinates of any point on it are given by (at2,2at)(at^2, 2at). Since a=1a=1 for our parabola, the parametric coordinates of a point are (t2,2t)(t^2, 2t).

Why use parametric form? Parametric representation is incredibly

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