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JEE Main 2023
Conic Sections
Parabola
Medium

Question

If the tangent at a point P on the parabola y2=3xy^2=3x is parallel to the line x+2y=1x+2y=1 and the tangents at the points Q and R on the ellipse x24+y21=1\frac{x^2}{4}+\frac{y^2}{1}=1 are perpendicular to the line xy=2x-y=2, then the area of the triangle PQR is :

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Solution

This problem integrates concepts from coordinate geometry, specifically properties of tangents to parabolas and ellipses, and the formula for the area of a triangle. We will systematically find the coordinates of points P, Q, and R, and then calculate the area of the triangle formed by them.


1. Finding Point P on the Parabola

Key Concept: For a parabola of the form y2=4axy^2 = 4ax, the equation of the tangent with slope mm is y=mx+amy = mx + \frac{a}{m}. The point of tangency corresponding to this tangent is P(am2,2am)P\left(\frac{a}{m^2}, \frac{2a}{m}\right).

Step-by-step Derivation:

  1. **Identify

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