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JEE Main 2021
Conic Sections
Parabola
Easy

Question

If the tangents drawn at the points P\mathrm{P} and Q\mathrm{Q} on the parabola y2=2x3y^{2}=2 x-3 intersect at the point R(0,1)R(0,1), then the orthocentre of the triangle PQRP Q R is :

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Solution

The problem asks us to find the orthocentre of a triangle PQR, where P and Q are points on the parabola y2=2x3y^2 = 2x-3, and R is the intersection point of the tangents drawn to the parabola at P and Q. The point R is given as (0,1)(0,1).

To solve this, we will first identify the coordinates of P and Q, then the slopes of the sides of PQR\triangle PQR, and finally determine the orthocentre by finding the intersection of two altitudes.


1. Standardizing the Parabola Equation and Finding Key Parameters

The given parabola equation is y2=2x3y^2 = 2x - 3. To work with it more easily, we can rewrite it in the standard form $Y

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