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JEE Main 2023
Conic Sections
Parabola
Medium

Question

Let ABCD be a trapezium whose vertices lie on the parabola y2=4x\mathrm{y}^2=4 \mathrm{x}. Let the sides AD and BC of the trapezium be parallel to yy-axis. If the diagonal AC is of length 254\frac{25}{4} and it passes through the point (1,0)(1,0), then the area of ABCDA B C D is

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Solution

This problem involves finding the area of a trapezium whose vertices lie on a parabola, utilizing properties of focal chords and geometric formulas.


1. Understanding the Parabola and Parametric Representation

The given parabola is y2=4xy^2 = 4x. This is of the standard form y2=4axy^2 = 4ax, where a=1a=1. The focus of this parabola is at (a,0)(a,0), which is (1,0)(1,0).

Any point on the parabola y2=4xy^2 = 4x can be represented parametrically as P(t)=(t2,2t)P(t) = (t^2, 2t) for some real parameter tt. This representation is extremely useful for calculations involving points on the parabola.

**2. Defining the Vertices of the Trapezium

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