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JEE Main 2023
Conic Sections
Ellipse
Hard

Question

Let for two distinct values of p the lines y=x+py=x+\mathrm{p} touch the ellipse E:x242+y232=1\mathrm{E}: \frac{x^2}{4^2}+\frac{y^2}{3^2}=1 at the points A and B . Let the line y=xy=x intersect E at the points C and D . Then the area of the quadrilateral ABCDA B C D is equal to :

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Solution

This problem combines several key concepts from coordinate geometry, specifically related to ellipses. We will use the condition for a line to be tangent to an ellipse, find the coordinates of the points of tangency and intersection, and finally calculate the area of the resulting quadrilateral.


1. Key Concept: Condition for Tangency to an Ellipse

For an ellipse given by the standard equation x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1, a line y=mx+cy = mx + c is tangent to the ellipse if and only if the condition c2=a2m2+b2c^2 = a^2m^2 + b^2 is satisfied. This is a fundamental result for ellipses and is crucial for finding the tangent lines.

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