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JEE Main 2023
Conic Sections
Hyperbola
Medium

Question

Let P(x0,y0)\mathrm{P}\left(x_{0}, y_{0}\right) be the point on the hyperbola 3x24y2=363 x^{2}-4 y^{2}=36, which is nearest to the line 3x+2y=13 x+2 y=1. Then 2(y0x0)\sqrt{2}\left(y_{0}-x_{0}\right) is equal to :

Options

Solution

1. Understanding the Problem and Key Concept

We are tasked with finding a specific point, let's call it P(x0,y0)P(x_0, y_0), on the hyperbola 3x24y2=363x^2 - 4y^2 = 36. This point must be the one closest to the given straight line 3x+2y=13x + 2y = 1. Once we find x0x_0 and y0y_0, our final goal is to compute the value of the expression 2(y0x0)\sqrt{2}(y_0 - x_0).

Key Concept: Point of Closest Approach For a point on a curve to be closest (or farthest) to a given straight line, the tangent to the curve at that point must be parallel to the

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