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Conic Sections
Parabola
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Question

Let the focal chord of the parabola P:y2=4x\mathrm{P}: y^{2}=4 x along the line L:y=mx+c,m>0\mathrm{L}: y=\mathrm{m} x+\mathrm{c}, \mathrm{m}>0 meet the parabola at the points M and N. Let the line L be a tangent to the hyperbola H:x2y2=4\mathrm{H}: x^{2}-y^{2}=4. If O is the vertex of P and F is the focus of H on the positive x-axis, then the area of the quadrilateral OMFN is :

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Solution

This solution provides a detailed and educational approach to solve the problem, highlighting the underlying mathematical concepts and step-by-step reasoning.


1. Deconstructing the Problem Statement and Identifying Key Information

The problem asks us to find the area of a quadrilateral OMFN formed by specific points related to a parabola and a hyperbola. Let's break down the given information:

  • Parabola P: y2=4xy^2 = 4x.
  • Hyperbola H: x2y2=4x^2 - y^2 = 4.
  • Line L: y=mx+cy = mx + c, with m>0m > 0. This line serves two purposes:
    1. It is a focal chord of the parabola P. This means it passes through the focus of P.
    2. It is a tangent to the hyperbola H. This means it touches the hyperbola at exactly one point.
  • Point O: The vertex of parabola P.
  • Point F: The focus of hyperbola H on the positive x-axis.
  • Points M and N: The intersection points of line L with parabola P.
  • Goal: Calculate the area of the quadrilateral OMFN.

To achieve this, we will systematically extract parameters from each conic section, use the given conditions for line L to determine its equation, find the coordinates of M and N, and finally calculate the area.

2. Analyzing Parabola P and Line L's Focal Chord Property

Key Concept: The standard equation of a parabola with its vertex at the origin and axis along the x-axis is y2=4axy^2 = 4ax. Its focus is located at (a,0)(a,0). A focal chord is a line segment that passes through the focus of the parabola.

Step 1: Identify the parameter 'a' for Parabola P. The given parabola is P:y2=4xP: y^2 = 4x. Comparing this with the standard form y2=4axy^2 = 4ax, we can see that 4a=44a = 4. Therefore, a=1a = 1.

Step 2: Determine the Focus of Parabola P. Since a=1a=1, the focus of parabola P is at (a,0)(a,0), which is (1,0)(1,0). Let's denote this as FP=(1,0)F_P = (1,0).

Step 3: Apply the Focal Chord Condition to Line L. The line L:y=mx+cL: y = mx + c is a focal chord of P, meaning it must pass through the focus FP(1,0)F_P(1,0). Substitute the coordinates of FPF_P into the equation of line L: 0=m(1)+c0 = m(1) + c c=m\Rightarrow c = -m So, the equation of line L can be partially determined as y=mxm=m(x1)y = mx - m = m(x-1).

Tip: Always start by identifying the fundamental parameters (aa for parabola, aH,bHa_H, b_H for hyperbola) as they are the building blocks for further calculations. The definition of a focal chord is crucial here.

3. Analyzing Hyperbola H and Line L's Tangency Property

Key Concept: The standard equation of a hyperbola centered at the origin, opening along the x-axis, is x2aH2y2bH2=1\frac{x^2}{a_H^2} - \frac{y^2}{b_H^2} = 1. Its foci are at (±aHeH,0)(\pm a_H e_H, 0), where eHe_H is the eccentricity. The condition for a line y=mx+cy = mx + c to be tangent to the hyperbola x2aH2y2bH2=1\frac{x^2}{a_H^2} - \frac{y^2}{b_H^2} = 1 is c2=aH2m2bH2c^2 = a_H^2 m^2 - b_H^2.

Step 1: Convert Hyperbola H to Standard Form and Identify aH,bHa_H, b_H. The given hyperbola is H:x2y2=4H: x^2 - y^2 = 4. To get it into standard form, divide the entire equation by 4: x24y24=1\frac{x^2}{4} - \frac{y^2}{4} = 1 Comparing this with x2aH2y2bH2=1\frac{x^2}{a_H^2} - \frac{y^2}{b_H^2} = 1, we identify: aH2=4aH=2a_H^2 = 4 \Rightarrow a_H = 2 (since aH>0a_H > 0) bH2=4bH=2b_H^2 = 4 \Rightarrow b_H = 2

Step 2: Calculate the Eccentricity (eHe_H) of Hyperbola H. For a hyperbola, the eccentricity is given by the formula eH=1+bH2aH2e_H = \sqrt{1 + \frac{b_H^2}{a_H^2}}. eH=1+44=1+1=2e_H = \sqrt{1 + \frac{4}{4}} = \sqrt{1+1} = \sqrt{2}

Step 3: Determine the Focus F of Hyperbola H. The foci of this hyperbola are at (±aHeH,0)(\pm a_H e_H, 0). Since we are given that F is the focus on the positive x-axis, its coordinates are (aHeH,0)(a_H e_H, 0). F=(22,0)=(22,0)F = (2 \cdot \sqrt{2}, 0) = (2\sqrt{2}, 0)

Step 4: Apply the Tangency Condition for Line L to Hyperbola H. Line L:y=mx+cL: y = mx + c is tangent to H:x24y24=1H: \frac{x^2}{4} - \frac{y^2}{4} = 1. Using the tangency condition c2=aH2m2bH2c^2 = a_H^2 m^2 - b_H^2: c2=(2)2m2(2)2c^2 = (2)^2 m^2 - (2)^2 c2=4m24c^2 = 4m^2 - 4

Tip: Be careful with the tangency condition; it varies for different conic sections. For a hyperbola x2a2y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1, it's c2=a2m2b2c^2 = a^2m^2 - b^2. For an ellipse x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1, it's c2=a2m2+b2c^2 = a^2m^2 + b^2.

4. Determining the Equation of Line L

Key Concept: We have derived two conditions for the constants mm and cc of line L: c=mc = -m (from focal chord property) and c2=4m24c^2 = 4m^2 - 4 (from tangency property). We can now combine these to find the specific values of mm and cc.

**Step 1: Substitute the expression for 'c'

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