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Conic Sections
Parabola
Medium

Question

Let the shortest distance from (a,0),a>0(a, 0), a>0, to the parabola y2=4xy^2=4 x be 4 . Then the equation of the circle passing through the point (a,0)(a, 0) and the focus of the parabola, and having its centre on the axis of the parabola is :

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Solution

This problem beautifully integrates concepts from coordinate geometry, specifically the properties of parabolas and circles. The first critical step involves finding the shortest distance from an external point to a curve, a common application that often involves calculus or the geometric property of normals.


1. Key Concept: Shortest Distance from a Point to a Curve

The shortest distance from an external point to a curve occurs along the normal drawn from that point to the curve. This is because the normal is perpendicular to the tangent at the point of contact. The distance vector from the external point to the point of contact on the curve will be perpendicular to the curve's direction at that point, which is a fundamental condition for minimum distance.

For a parabola y2=4pxy^2=4px, the general equation of a normal at a

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