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Conic Sections
Parabola
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Question

The equation of a common tangent to the parabolas y=x2y=x^{2} and y=(x2)2y=-(x-2)^{2} is

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Solution

1. Key Concept: Equation of a Tangent to a Parabola

A common and efficient way to find the equation of a common tangent to two curves is to express the general equation of a tangent for each curve in terms of its slope, say mm. If a line y=mx+cy = mx + c is tangent to both curves, then the yy-intercept cc derived from each curve must be the same for the same slope mm.

For a parabola of the form x2=4Ayx^2 = 4Ay, the equation of a tangent line with slope mm is given by: y=mxAm2y = mx - Am^2 This formula is derived by finding the derivative dydx=x2A\frac{dy}{dx} = \frac{x}{2A},

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