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JEE Main 2024
Conic Sections
Hyperbola
Hard

Question

The length of the latus rectum and directrices of hyperbola with eccentricity e are 9 and x=±43x= \pm \frac{4}{\sqrt{3}}, respectively. Let the line y3x+3=0y-\sqrt{3} x+\sqrt{3}=0 touch this hyperbola at (x0,y0)\left(x_0, y_0\right). If m\mathrm{m} is the product of the focal distances of the point (x0,y0)\left(x_0, y_0\right), then 4e2+m4 \mathrm{e}^2+\mathrm{m} is equal to _________.

Answer: 2

Solution

This solution aims to provide a detailed, step-by-step approach to solving the given hyperbola problem. We will systematically use the properties of hyperbolas, tangent conditions, and focal distances to arrive at the final answer.


1. Understanding the Hyperbola and its Standard Equations

A hyperbola centered at the origin with its transverse axis along the x-axis has the standard equation: x2a2y2b2=1\frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 where aa is the semi-transverse axis length and bb is the semi-conjugate axis length. Key formulas for such a hyperbola are:

  • Eccentricity ee: $b^2 = a

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