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Conic Sections
Hyperbola
Easy

Question

The normal to the hyperbola x2a2y29=1{{{x^2}} \over {{a^2}}} - {{{y^2}} \over 9} = 1 at the point (8,33)\left( {8,3\sqrt 3 } \right) on it passes through the point :

Options

Solution

This solution will guide you through finding the equation of the normal to a hyperbola at a given point and then determining which of the provided options lies on that normal.

Key Concept: Equation of the Normal to a Hyperbola

For a hyperbola centered at the origin with its equation given in the standard form: x2A2y2B2=1\frac{x^2}{A^2} - \frac{y^2}{B^2} = 1 the equation of the normal line at a point P(x1,y1)P(x_1, y_1) lying on the hyperbola is given by: A2xx1+B2yy1=A2+B2\frac{A^2x}{x_1} + \frac{B^2y}{y_1} = A^2 + B^2

**Derivation

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