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Conic Sections
Parabola
Hard

Question

The area (in sq. units) of an equilateral triangle inscribed in the parabola y 2 = 8x, with one of its vertices on the vertex of this parabola, is :

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Solution

Here's an elaborate, clear, and educational solution to the problem, designed for a JEE student.


1. Understanding the Parabola and its Vertex

The given equation of the parabola is y2=8xy^2 = 8x. Why this step is important: We need to identify the key features of the parabola to correctly place the triangle.

  • This equation is in the standard form y2=4axy^2 = 4ax.
  • By comparing y2=8xy^2 = 8x with y2=4axy^2 = 4ax, we find 4a=84a = 8, which implies a=2a = 2.
  • The vertex of this parabola is at the origin, A=(0,0)A = (0,0).
  • The

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