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JEE Main 2024
Definite Integration
Definite Integration
Hard

Question

The integral 24π02(2x2)dx(2+x2)4+x4{{24} \over \pi }\int_0^{\sqrt 2 } {{{(2 - {x^2})dx} \over {(2 + {x^2})\sqrt {4 + {x^4}} }}} is equal to ____________.

Answer: 24

Solution

This integral is a classic example of how algebraic manipulation and appropriate substitutions can simplify complex expressions into standard integrable forms. The key strategy involves identifying patterns and using substitutions that transform the integrand into a more manageable structure, often involving terms like x2+1/x2x^2 + 1/x^2 or x1/xx - 1/x.


1. Initial Setup and Analysis of the Integral

We are asked to evaluate the definite integral: I=24π02(2x2)dx(2+x2)4+x4I = {{24} \over \pi }\int_0^{\sqrt 2 } {{{(2 - {x^2})dx} \over {(2 + {x^2})\sqrt {4 + {x^4}} }}}

The integrand contains terms involving x2x^2 and x4x^4. The

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