Key Concepts and Formulas
- Functional Equation: An equation where the unknown is a function. Solving often involves substitution and differentiation.
- Differential Equations: Equations involving derivatives. Separable equations are of the form dxdy=g(x)h(y), solved by separating variables and integrating.
- Logarithm Properties: loge(ab)=bloge(a).
- Arithmetic Series: ∑k=1nk=2n(n+1).
Step-by-Step Solution
Step 1: Analyze the Given Information
We are given the functional equation
f(x+y)=f(x)f′(y)+f′(x)f(y)(∗)
and the initial condition f(0)=1. We need to find ∑n=1100logef(n).
Step 2: Find f′(0)
To find f′(0), substitute x=0 and y=0 into the functional equation (∗):
f(0+0)=f(0)f′(0)+f′(0)f(0)
f(0)=2f(0)f′(0)
Since f(0)=1, we have
1=2(1)f′(0)
f′(0)=21
Step 3: Derive a Differential Equation
Substitute y=0 into the functional equation (∗):
f(x+0)=f(x)f′(0)+f′(x)f(0)
f(x)=f(x)f′(0)+f′(x)f(0)
Substitute f(0)=1 and f′(0)=21:
f(x)=f(x)(21)+f′(x)(1)
f(x)=21f(x)+f′(x)
f′(x)=21f(x)
Step 4: Solve the Differential Equation
We have the differential equation
dxdf=21f(x)
Separate the variables:
f(x)df=21dx
Integrate both sides:
∫f(x)df=∫21dx
ln∣f(x)∣=21x+C
Exponentiate both sides:
∣f(x)∣=e21x+C=e21xeC
f(x)=Ae21x
where A=±eC is a constant.
Step 5: Determine the Constant A
Use the initial condition f(0)=1:
f(0)=Ae21(0)=Ae0=A
Since f(0)=1, we have A=1. Therefore,
f(x)=e2x
Step 6: Evaluate the Summation
We need to find
S=∑n=1100logef(n)=∑n=1100loge(e2n)
Using the property loge(ek)=k, we have
S=∑n=11002n=21∑n=1100n
Using the formula for the sum of the first n natural numbers, ∑k=1nk=2n(n+1), we get
S=21(2100(100+1))=21(2100(101))=21(210100)=410100=2525
Common Mistakes & Tips
- Remember to use the initial condition to find the constant of integration after solving the differential equation.
- Don't forget the properties of logarithms when simplifying the summation.
- Double-check your calculations, especially when dealing with fractions and summations.
Summary
We used the given functional equation and initial condition to derive a differential equation for f(x). Solving this differential equation and applying the initial condition, we found f(x)=ex/2. Then, we evaluated the sum ∑n=1100logef(n), which simplifies to 21∑n=1100n. Using the arithmetic series formula, we found the sum to be 2525.
The final answer is \boxed{2525}. This corresponds to option (C).