JEE Main 2020
Differentiation
Differentiation
Medium
Question
Let f : R R be a function such that f(x) = x 3 + x 2 f'(1) + xf''(2) + f'''(3), x R. Then f(2) equals -
Options
Solution
f(x) = x 3 + x 2 f '(1) + xf ''(2) + f '''(3) f '(x) = 3x 2 + 2xf '(1) + f ''(x) . . . . . (1) f ''(x) = 6x + 2f '(1) . . . . . . (2) f '''(x) = 6 . . . . . .(3) put x = 1 in equation (1) : f '(1) = 3 + 2f '(1) + f ''(2) . . . . .(4) put x = 2 in equation (2) : f ''(2) = 12 + 2f '(1) . . . . .(5) from equation (4) & (5) : 3 f '(1) = 12 + 2f'(1) 3f '(1) = 15 f '(1) = 5 f ''(2) = 2 . . . . .(2) put x = 3 in equation (3) : f ''' (3) = 6 f(x) = x 3 5x 2 + 2x + 6 f(2) = 8 20 + 4 + 6 = 2