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JEE Main 2020
Differentiation
Differentiation
Medium

Question

Let f : R \to R be a function such that f(x) = x 3 + x 2 f'(1) + xf''(2) + f'''(3), x \in R. Then f(2) equals -

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Solution

f(x) = x 3 + x 2 f '(1) + xf ''(2) + f '''(3) \Rightarrow f '(x) = 3x 2 + 2xf '(1) + f ''(x) . . . . . (1) \Rightarrow f ''(x) = 6x + 2f '(1) . . . . . . (2) \Rightarrow f '''(x) = 6 . . . . . .(3) put x = 1 in equation (1) : f '(1) = 3 + 2f '(1) + f ''(2) . . . . .(4) put x = 2 in equation (2) : f ''(2) = 12 + 2f '(1) . . . . .(5) from equation (4) & (5) : -3 - f '(1) = 12 + 2f'(1) \Rightarrow 3f '(1) = - 15 \Rightarrow f '(1) = - 5 \Rightarrow f ''(2) = 2 . . . . .(2) put x = 3 in equation (3) : f ''' (3) = 6 \therefore f(x) = x 3 - 5x 2 + 2x + 6 f(2) = 8 - 20 + 4 + 6 = - 2

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