JEE Main 2019
Height and Distance
Height and Distance
Easy
Question
ABC is a triangular park with AB = AC = 100 metres. A vertical tower is situated at the mid-point of BC. If the angles of elevation of the top of the tower at A and B are cot –1 (3 ) and cosec –1 (2 ) respectively, then the height of the tower (in metres) is :
Options
Solution
APM BPM ABM AM 2 + MB 2 = (100) 2 ' 18h 2 + 7h 2 = 100 × 100 h 2 = 4 × 100 h = 20