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Height and Distance
Height and Distance
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Question

Two vertical poles are 150 m apart and the height of one is three times that of the other. If from the middle point of the line joining their feet, an observer finds the angles of elevation of their tops to be complementary, then the height of the shorter pole (in meters) is :

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Solution

\therefore tan(90θ)=x75\tan (90 - \theta ) = {x \over {75}} and tanθ=3x75\tan \theta = {{3x} \over {75}} As cotθ.tanθ=1\cot \theta .\tan \theta = 1 \therefore x75.3x75=1{x \over {75}}.{{3x} \over {75}} = 1 x=253\Rightarrow x = 25\sqrt 3

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