Power Rule for Integration: ∫xndx=n+1xn+1+C, where n=−1
Step-by-Step Solution
Step 1: Rewrite the integral using trigonometric identities.
The goal is to express the integrand in terms of sine and cosine to simplify it.
I=∫sec2/3xcsc4/3xdx=∫cos2/3x1⋅sin4/3x1dx
Step 2: Manipulate the expression to isolate csc2x and cotx.
We want to create a form where we can use substitution, specifically involving cotx and its derivative. To do this, we rewrite the expression to isolate a csc2x term.
Let t=cotx. Then, dt=−csc2xdx, so csc2xdx=−dt.
I=∫t2/3−dt=−∫t−2/3dt
Step 4: Evaluate the integral using the power rule.
I=−(−2/3)+1t(−2/3)+1+C=−1/3t1/3+C=−3t1/3+C
Step 5: Substitute back for x.
Substitute t=cotx back into the expression.
I=−3(cotx)1/3+C=−33cotx+C
Step 6: Rewrite in terms of tangent.
Since cotx=tanx1, we have
I=−3(tanx1)1/3+C=−3(tanx)−1/3+C=−3tan−1/3x+C
Common Mistakes & Tips
Be careful with the signs during u-substitution.
Remember to substitute back to the original variable after integration.
When dealing with trigonometric integrals, look for opportunities to use trigonometric identities to simplify the expression.
Summary
We started by rewriting the integral using trigonometric identities to get it in terms of sine and cosine. We then manipulated the expression to isolate csc2x and cotx to perform a u-substitution with t=cotx. After integrating and substituting back, we expressed the result in terms of tanx to match one of the answer choices.
Final Answer
The final answer is \boxed{-3 \tan^{-1/3} x + C}, which corresponds to option (D).