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JEE Main 2024
Inverse Trigonometric Functions
Inverse Trigonometric Functions
Medium

Question

If sin1α17+cos145tan17736=0,0<α<13{\sin ^{ - 1}}{\alpha \over {17}} + {\cos ^{ - 1}}{4 \over 5} - {\tan ^{ - 1}}{{77} \over {36}} = 0,0 < \alpha < 13, then sin1(sinα)+cos1(cosα){\sin ^{ - 1}}(\sin \alpha ) + {\cos ^{ - 1}}(\cos \alpha ) is equal to :

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Solution

sin1(α17)=cos4(45)+tan1(7736)\sin ^{-1}\left(\frac{\alpha}{17}\right)=-\cos ^{4}\left(\frac{4}{5}\right)+\tan ^{-1}\left(\frac{77}{36}\right) Let cos1(45)=p\cos ^{-1}\left(\frac{4}{5}\right)=p and tan1(7736)=q\tan ^{-1}\left(\frac{77}{36}\right)=q sin(sin1α17)=sin(qp)\Rightarrow \sin \left(\sin ^{-1} \frac{\alpha}{17}\right)=\sin (q-p) =sinqcospcosqsinp=\sin q \cdot \cos p-\cos q \cdot \sin p α17=778545368535\Rightarrow \frac{\alpha}{17}=\frac{77}{85} \cdot \frac{4}{5}-\frac{36}{85} \cdot \frac{3}{5} α=20025=8\Rightarrow \alpha=\frac{200}{25}=8 sin1sin8+cos1cos8\sin ^{-1} \sin 8+\cos ^{-1} \cos 8 =8+3π+82π= -8+3 \pi+8-2 \pi =π=\pi

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