If sin−117α+cos−154−tan−13677=0,0<α<13, then sin−1(sinα)+cos−1(cosα) is equal to :
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Solution
sin−1(17α)=−cos4(54)+tan−1(3677) Let cos−1(54)=p and tan−1(3677)=q⇒sin(sin−117α)=sin(q−p)=sinq⋅cosp−cosq⋅sinp⇒17α=8577⋅54−8536⋅53⇒α=25200=8sin−1sin8+cos−1cos8=−8+3π+8−2π=π