JEE Main 2018Inverse Trigonometric FunctionsInverse Trigonometric FunctionsEasyQuestionThe domain of the function cosec−1(1+xx){{\mathop{\rm cosec}\nolimits} ^{ - 1}}\left( {{{1 + x} \over x}} \right)cosec−1(x1+x) is :OptionsA(−1,−12]∪(0,∞)\left( { - 1, - {1 \over 2}} \right] \cup (0,\infty )(−1,−21]∪(0,∞)B[−12,0)∪[1,∞)\left[ { - {1 \over 2},0} \right) \cup [1,\infty )[−21,0)∪[1,∞)C(−12,∞)−{0}\left( { - {1 \over 2},\infty } \right) - \{ 0\} (−21,∞)−{0}D[−12,∞)−{0}\left[ { - {1 \over 2},\infty } \right) - \{ 0\} [−21,∞)−{0}Check AnswerHide SolutionSolution1+xx∈(−∞,−1]∪[1,∞){{1 + x} \over x} \in ( - \infty , - 1] \cup [1,\infty )x1+x∈(−∞,−1]∪[1,∞) 1x∈(−∞,−2]∪[0,∞){1 \over x} \in ( - \infty , - 2] \cup [0,\infty )x1∈(−∞,−2]∪[0,∞) x∈[−12,0)∪(0,∞)x \in \left[ { - {1 \over 2},0} \right) \cup (0,\infty )x∈[−21,0)∪(0,∞) x∈[−12,0)∪{0}x \in \left[ { - {1 \over 2},0} \right) \cup \{ 0\} x∈[−21,0)∪{0}