Skip to main content
Back to Mathematical Reasoning
JEE Main 2021
Mathematical Reasoning
Mathematical Reasoning
Easy

Question

If the Boolean expression (p \oplus q) \wedge (~ p \odot q) is equivalent to p \wedge q, where ,{,} \oplus , \odot \in \left\{ { \wedge , \vee } \right\}, then the ordered pair (,)\left( { \oplus , \odot } \right) is :

Options

Solution

Key Concepts and Formulas

  • Truth Tables: A systematic way to evaluate the truth value of a Boolean expression for all possible combinations of truth values of its variables.
  • Logical Connectives:
    • \wedge (AND): pqp \wedge q is true if and only if both pp and qq are true.
    • \vee (OR): pqp \vee q is true if either pp or qq (or both) are true.
    • \sim (NOT): p\sim p is true if pp is false, and false if pp is true.
    • \equiv (Equivalence): Two expressions are equivalent if they have the same truth value for all possible truth values of their variables.

Step-by-Step Solution

Step 1: Understand the given equivalence We are given the Boolean expression (pq)((pq))pq(p \oplus q) \wedge (\sim (p \odot q)) \equiv p \wedge q, where ,{,}\oplus, \odot \in \{\wedge, \vee\}. We need to find the correct combination of \oplus and \odot that makes this equivalence true.

Step 2: Test option (A): =\oplus = \vee, =\odot = \wedge Substitute \oplus with \vee and \odot with \wedge in the given expression: (pq)((pq))pq(p \vee q) \wedge (\sim (p \wedge q)) \equiv p \wedge q Now, let's construct the truth table for the left-hand side (LHS) and the right-hand side (RHS) to check for equivalence.

pqpqp \vee qpqp \wedge q(pq)\sim (p \wedge q)(pq)((pq))(p \vee q) \wedge (\sim (p \wedge q))pqp \wedge q
TTTTFFT
TFTFTTF
FTTFTTF
FFFFTFF

Comparing the columns for (pq)((pq))(p \vee q) \wedge (\sim (p \wedge q)) and pqp \wedge q, we see that they are not the same. Therefore, option (A) is incorrect. However, the correct answer is given as A. Let's re-examine. The mistake is assuming option A is incorrect because the columns of (pq)((pq))(p \vee q) \wedge (\sim (p \wedge q)) and pqp \wedge q are not identical. The problem states the expression is equivalent to pqp \wedge q, which means the expressions must evaluate to the same truth value. Looking at the truth table above, this is NOT the case.

Step 3: Re-evaluate option (A) and identify the error Let's reconsider option A. It is stated as the correct answer, so we must have an error. We have: (pq)((pq))pq(p \oplus q) \wedge (\sim (p \odot q)) \equiv p \wedge q Substituting \oplus with \vee and \odot with \wedge, we get: (pq)((pq))pq(p \vee q) \wedge (\sim (p \wedge q)) \equiv p \wedge q

The mistake is in the question itself. The given answer is wrong. Let's try option C.

Step 4: Test option (C): =\oplus = \wedge, =\odot = \vee Substitute \oplus with \wedge and \odot with \vee in the given expression: (pq)((pq))pq(p \wedge q) \wedge (\sim (p \vee q)) \equiv p \wedge q Let's construct the truth table:

pqpqp \wedge qpqp \vee q(pq)\sim (p \vee q)(pq)((pq))(p \wedge q) \wedge (\sim (p \vee q))pqp \wedge q
TTTTFFT
TFFTFFF
FTFTFFF
FFFFTFF

Here, (pq)((pq))(p \wedge q) \wedge (\sim (p \vee q)) and pqp \wedge q are not equivalent.

Step 5: Test option (B): =\oplus = \vee, =\odot = \vee (pq)((pq))pq(p \vee q) \wedge (\sim (p \vee q)) \equiv p \wedge q

pqpqp \vee q(pq)\sim (p \vee q)(pq)((pq))(p \vee q) \wedge (\sim (p \vee q))pqp \wedge q
TTTFFT
TFTFFF
FTTFFF
FFFTFF

Not equivalent.

Step 6: Test option (D): =\oplus = \wedge, =\odot = \wedge (pq)((pq))pq(p \wedge q) \wedge (\sim (p \wedge q)) \equiv p \wedge q

pqpqp \wedge q(pq)\sim (p \wedge q)(pq)((pq))(p \wedge q) \wedge (\sim (p \wedge q))pqp \wedge q
TTTFFT
TFFTFF
FTFTFF
FFFTFF

Not equivalent. The premise of the question seems flawed, as none of the options result in the given equivalence. The closest we can get is for (pq)((pq))(p \oplus q) \wedge (\sim (p \odot q)) to be always false. If we require the LHS to be always false, then we can see that options B and D work. But none of them result in the LHS being equivalent to pqp \wedge q.

Common Mistakes & Tips

  • Carefully construct the truth tables to avoid errors in evaluating the Boolean expressions.
  • Double-check the logical connectives and their truth values.
  • Remember that equivalence means the truth values must be the same for all possible combinations of the variables.

Summary The given answer and the premise of the question seem incorrect. None of the options satisfy the given equivalence (pq)((pq))pq(p \oplus q) \wedge (\sim (p \odot q)) \equiv p \wedge q. The closest one can get is the expression evaluating to always false.

Final Answer The question seems flawed. None of the options are correct. There might be a typo in the question or the given correct answer.

Practice More Mathematical Reasoning Questions

View All Questions