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Mathematical Reasoning
Mathematical Reasoning
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Question

Negation of the statement : 5\sqrt 5 is an integer or 5 is an irrational is :

Options

Solution

Key Concepts and Formulas

  • Negation of a Disjunction: The negation of a statement of the form "p or q" (denoted pqp \vee q) is "not p and not q" (denoted pq\sim p \wedge \sim q). This is De Morgan's Law: (pq)pq\sim(p \vee q) \equiv \sim p \wedge \sim q.
  • Negation of a Statement: The negation of a statement reverses its truth value. For example, the negation of "x is an integer" is "x is not an integer".

Step-by-Step Solution

Step 1: Identify the component statements. Let pp be the statement "5\sqrt{5} is an integer" and let qq be the statement "5 is irrational." The given statement is pqp \vee q.

Step 2: Express the negation of the given statement using symbolic logic. We want to find the negation of pqp \vee q, which is (pq)\sim(p \vee q).

Step 3: Apply De Morgan's Law. Using De Morgan's Law, (pq)pq\sim(p \vee q) \equiv \sim p \wedge \sim q.

Step 4: Translate the symbolic negation back into words. p\sim p is the statement "5\sqrt{5} is not an integer." q\sim q is the statement "5 is not irrational." Therefore, pq\sim p \wedge \sim q is the statement "5\sqrt{5} is not an integer and 5 is not irrational."

Common Mistakes & Tips

  • Remember De Morgan's Laws. It's a common mistake to incorrectly negate a disjunction.
  • Pay close attention to the wording of the statements. "Not irrational" is equivalent to "rational". However, sticking directly to "not irrational" avoids potential confusion.

Summary

We are asked to find the negation of the statement "5\sqrt{5} is an integer or 5 is irrational." First, we represent the two component statements as pp and qq respectively. The given statement is pqp \vee q. The negation of this statement is (pq)\sim(p \vee q), which, by De Morgan's Law, is equivalent to pq\sim p \wedge \sim q. Translating back into words, this is "5\sqrt{5} is not an integer and 5 is not irrational."

Final Answer The final answer is \boxed{5\sqrt 5 is not an integer and 5 is not irrational.}, which corresponds to option (A).

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