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JEE Main 2023
Mathematical Reasoning
Mathematical Reasoning
Easy

Question

Let p, q, r be three logical statements. Consider the compound statements S1:((p)q)((p)r){S_1}:(( \sim p) \vee q) \vee (( \sim p) \vee r) and S2:p(qr){S_2}:p \to (q \vee r) Then, which of the following is NOT true?

Options

Solution

Key Concepts and Formulas

  • Logical OR (∨): The statement ABA \vee B is true if at least one of AA or BB is true. It is only false if both AA and BB are false.
  • Logical NOT (∼): The statement A\sim A is true if AA is false, and vice versa.
  • Conditional Statement (→): The statement ABA \to B is equivalent to (A)B(\sim A) \vee B. The statement ABA \to B is only false when AA is true and BB is false.
  • Associative Law for OR: (AB)CA(BC)(A \vee B) \vee C \equiv A \vee (B \vee C). This means we can drop parentheses when dealing with only OR operations.

Step-by-Step Solution

Step 1: Simplify S<sub>1</sub>

Our goal is to simplify S1S_1 using the associative property of the OR operator. S1:((p)q)((p)r)S_1: ((\sim p) \vee q) \vee ((\sim p) \vee r) Since the OR operation is associative, we can rewrite S1S_1 as: S1:(p)q(p)rS_1: (\sim p) \vee q \vee (\sim p) \vee r Since OR operation is idempotent (AAAA \vee A \equiv A), we can further simplify by combining the p\sim p terms: S1:(p)(p)qrS_1: (\sim p) \vee (\sim p) \vee q \vee r S1:(p)qrS_1: (\sim p) \vee q \vee r

Step 2: Simplify S<sub>2</sub>

Our goal is to rewrite S2S_2 using the definition of the conditional statement. S2:p(qr)S_2: p \to (q \vee r) Using the equivalence AB(A)BA \to B \equiv (\sim A) \vee B, we can rewrite S2S_2 as: S2:(p)(qr)S_2: (\sim p) \vee (q \vee r) Due to the associative property of OR, we can rewrite it as: S2:(p)qrS_2: (\sim p) \vee q \vee r

Step 3: Compare S<sub>1</sub> and S<sub>2</sub>

We have simplified both S1S_1 and S2S_2: S1:(p)qrS_1: (\sim p) \vee q \vee r S2:(p)qrS_2: (\sim p) \vee q \vee r Therefore, S1S_1 and S2S_2 are logically equivalent. This means they always have the same truth value. If S1S_1 is true, S2S_2 is true, and if S1S_1 is false, S2S_2 is false.

Step 4: Analyze the Options

Now we analyze each option to determine which one is NOT true:

  • (A) If S<sub>2</sub> is True, then S<sub>1</sub> is True: Since S1S_1 and S2S_2 are equivalent, this statement is true.
  • (B) If S<sub>2</sub> is False, then S<sub>1</sub> is False: Since S1S_1 and S2S_2 are equivalent, this statement is true.
  • (C) If S<sub>2</sub> is False, then S<sub>1</sub> is True: Since S1S_1 and S2S_2 are equivalent, if S2S_2 is false, then S1S_1 must also be false. Therefore, this statement is false.
  • (D) If S<sub>1</sub> is False, then S<sub>2</sub> is False: Since S1S_1 and S2S_2 are equivalent, this statement is true.

Step 5: Identify the Incorrect Option

We found that option (C) is NOT true.

Common Mistakes & Tips

  • Confusion with Logical Equivalences: Remember the fundamental equivalences, particularly AB(A)BA \to B \equiv (\sim A) \vee B.
  • Associativity and Commutativity: Recognize and utilize the associative and commutative properties of logical operators to simplify expressions.
  • Truth Tables: When in doubt, constructing a truth table can help verify the equivalence of logical statements.

Summary

We simplified the given compound statements S1S_1 and S2S_2 using logical equivalences and the associative property of the OR operator. We found that S1S_1 and S2S_2 are logically equivalent. Therefore, statements (B) and (D) are true. Statement (A) is also true. Statement (C) is false, which is the answer.

Final Answer

The final answer is \boxed{A}, which corresponds to option (A).

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