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JEE Main 2021
Mathematical Reasoning
Mathematical Reasoning
Easy

Question

The conditional statement ((pq)((p)r))(((p)r)(pq))((p \wedge q) \to (( \sim p) \vee r)) \vee ((( \sim p) \vee r) \to (p \wedge q)) is :

Options

Solution

Key Concepts and Formulas

  • Conditional Statement: The conditional statement pqp \to q is false only when pp is true and qq is false. Otherwise, it is true.
  • Tautology: A tautology is a compound statement that is always true, regardless of the truth values of its individual components.
  • Truth Table: A truth table is a table that shows all possible combinations of truth values for a compound statement.

Step-by-Step Solution

Step 1: Define the component statements

Let's define the following statements to simplify the given expression:

  • A=pqA = p \wedge q
  • B=(p)rB = (\sim p) \vee r

The given statement can then be rewritten as: (AB)(BA)(A \to B) \vee (B \to A)

Step 2: Construct the truth table for A and B

We create a truth table to determine the truth values of AA and BB for all possible combinations of pp, qq, and rr. We also need the truth value of p\sim p.

ppqqrrp\sim pA=pqA = p \wedge qB=(p)rB = (\sim p) \vee r
TTTFTT
TTFFTF
TFTFFT
TFFFFF
FTTTFT
FTFTFT
FFTTFT
FFFTFT

Step 3: Construct the truth table for (AB)(A \to B) and (BA)(B \to A)

Now, we find the truth values of the conditional statements (AB)(A \to B) and (BA)(B \to A) using the truth values of AA and BB from the previous step.

ppqqrrp\sim pA=pqA = p \wedge qB=(p)rB = (\sim p) \vee rABA \to BBAB \to A
TTTFTTTT
TTFFTFFT
TFTFFTTF
TFFFFFTT
FTTTFTTF
FTFTFTTF
FFTTFTTF
FFFTFTTF

Step 4: Construct the truth table for (AB)(BA)(A \to B) \vee (B \to A)

Finally, we find the truth value of the disjunction (AB)(BA)(A \to B) \vee (B \to A) using the truth values of (AB)(A \to B) and (BA)(B \to A) from the previous step.

ppqqrrp\sim pA=pqA = p \wedge qB=(p)rB = (\sim p) \vee rABA \to BBAB \to A(AB)(BA)(A \to B) \vee (B \to A)
TTTFTTTTT
TTFFTFFTT
TFTFFTTFT
TFFFFFTTT
FTTTFTTFT
FTFTFTTFT
FFTTFTTFT
FFFTFTTFT

Step 5: Analyze the truth table

Observe that the last column, which represents the truth value of the given statement, always has the value 'T' (True) regardless of the values of pp, qq, and rr. Therefore, the given statement is a tautology.

Common Mistakes & Tips

  • Be very careful when evaluating conditional statements. Remember that pqp \to q is only false when pp is true and qq is false.
  • When creating truth tables, ensure that you consider all possible combinations of truth values for the component statements.
  • Recognize the logical equivalence: (pq)(qp)(p \to q) \vee (q \to p) is always a tautology.

Summary

By breaking down the given conditional statement into smaller components and constructing a truth table, we have shown that the statement is always true, regardless of the truth values of pp, qq, and rr. Therefore, the given statement is a tautology.

Final Answer

The final answer is \boxed{a tautology}, which corresponds to option (A).

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