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JEE Main 2020
Mathematical Reasoning
Mathematical Reasoning
Easy

Question

The maximum number of compound propositions, out of p\veer\vees, p\veer\vee$$$$\sims, p\vee$$$$\simq\vees, \simp\vee$$$$\simr\vees, \simp\vee$$$$\simr\vee$$$$\sims, \simp\veeq\vee$$$$\sims, q\veer\vee$$$$\sims, q\vee$$$$\simr\vee$$$$\sims, \simp\vee$$$$\simq\vee$$$$\sims that can be made simultaneously true by an assignment of the truth values to p, q, r and s, is equal to __________.

Answer: 9

Solution

Key Concepts and Formulas

  • Propositional Logic: Understanding the truth values (True/False) of propositions and how they combine using logical operators (∨ - OR, ∧ - AND, ∼ - NOT).
  • Truth Tables: Although not explicitly constructed here, the underlying principle is to find a truth assignment that satisfies the maximum number of given compound propositions.
  • Satisfiability: The problem revolves around finding a truth assignment to variables that makes a set of compound propositions simultaneously true.

Step-by-Step Solution

Step 1: Analyze the given propositions and identify a common element. We are given the following nine compound propositions:

  1. prsp \vee r \vee s
  2. prsp \vee r \vee \sim s
  3. pqsp \vee \sim q \vee s
  4. prs\sim p \vee \sim r \vee s
  5. prs\sim p \vee \sim r \vee \sim s
  6. pqs\sim p \vee q \vee \sim s
  7. qrsq \vee r \vee \sim s
  8. qrsq \vee \sim r \vee \sim s
  9. pqs\sim p \vee \sim q \vee \sim s

Notice that s\sim s appears in propositions 2, 5, 6, 7, 8, and 9. If we set ss to False, i.e., s=Fs = F, these six propositions will become true regardless of the values of p,q,p, q, and rr.

Step 2: Assign a truth value to 's' to maximize the number of initially satisfied propositions. Let's assign s=Fs = F. This makes the following propositions true: 2. prsprTTp \vee r \vee \sim s \equiv p \vee r \vee T \equiv T 3. prsprTT\sim p \vee \sim r \vee \sim s \equiv \sim p \vee \sim r \vee T \equiv T 4. pqspqTT\sim p \vee q \vee \sim s \equiv \sim p \vee q \vee T \equiv T 5. qrsqrTTq \vee r \vee \sim s \equiv q \vee r \vee T \equiv T 6. qrsqrTTq \vee \sim r \vee \sim s \equiv q \vee \sim r \vee T \equiv T 7. pqspqTT\sim p \vee \sim q \vee \sim s \equiv \sim p \vee \sim q \vee T \equiv T

Now we need to check if we can make the remaining propositions true as well.

Step 3: Analyze the remaining propositions with s = F. The remaining propositions are:

  1. prsprFprp \vee r \vee s \equiv p \vee r \vee F \equiv p \vee r
  2. pqspqFpqp \vee \sim q \vee s \equiv p \vee \sim q \vee F \equiv p \vee \sim q
  3. prsprFpr\sim p \vee \sim r \vee s \equiv \sim p \vee \sim r \vee F \equiv \sim p \vee \sim r

Step 4: Find values for p, q, and r to maximize the number of remaining true propositions. We want to make prp \vee r, pqp \vee \sim q, and pr\sim p \vee \sim r true.

Let's consider the case where p=Tp = T and r=Tr = T. Then:

  • prTTTp \vee r \equiv T \vee T \equiv T
  • pqTqTp \vee \sim q \equiv T \vee \sim q \equiv T
  • prFFF\sim p \vee \sim r \equiv F \vee F \equiv F

This doesn't work since pr\sim p \vee \sim r is false.

Let's try p=Tp = T and r=Fr = F. Then:

  • prTFTp \vee r \equiv T \vee F \equiv T
  • pqTqTp \vee \sim q \equiv T \vee \sim q \equiv T
  • prFTT\sim p \vee \sim r \equiv F \vee T \equiv T

This works! In this case, we can choose any value for qq, and all three remaining propositions will be true.

Step 5: Determine the maximum number of true propositions. If we set s=Fs = F, p=Tp = T, and r=Fr = F, the nine propositions become:

  1. prsTFFTp \vee r \vee s \equiv T \vee F \vee F \equiv T
  2. prsTFTTp \vee r \vee \sim s \equiv T \vee F \vee T \equiv T
  3. pqsTqFTp \vee \sim q \vee s \equiv T \vee \sim q \vee F \equiv T (since TqT \vee \sim q is always true)
  4. prsFTFT\sim p \vee \sim r \vee s \equiv F \vee T \vee F \equiv T
  5. prsFTTT\sim p \vee \sim r \vee \sim s \equiv F \vee T \vee T \equiv T
  6. pqsFqTT\sim p \vee q \vee \sim s \equiv F \vee q \vee T \equiv T
  7. qrsqFTTq \vee r \vee \sim s \equiv q \vee F \vee T \equiv T
  8. qrsqTTTq \vee \sim r \vee \sim s \equiv q \vee T \vee T \equiv T
  9. pqsFqTT\sim p \vee \sim q \vee \sim s \equiv F \vee \sim q \vee T \equiv T

Therefore, all 9 propositions can be made true simultaneously.

Common Mistakes & Tips

  • Overlooking Simplifications: Always simplify the propositions after assigning truth values to see if further simplification is possible.
  • Trying All Combinations: It is not necessary to check all 24=162^4 = 16 possible truth assignments. Start by looking for patterns that can satisfy multiple propositions simultaneously.
  • Misunderstanding the OR operator: Remember that ABA \vee B is true if either AA is true, BB is true, or both are true.

Summary

We analyzed the given compound propositions and identified a variable (s\sim s) that appeared frequently. By setting ss to False, we made six propositions automatically true. Then, we found values for pp and rr that made the remaining three propositions also true. Therefore, all nine propositions can be made simultaneously true by a suitable assignment of truth values.

Final Answer The final answer is \boxed{9}.

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