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JEE Main 2021
Mathematical Reasoning
Mathematical Reasoning
Easy

Question

The negation of the Boolean expression ~ s \vee (~r \wedge s) is equivalent to :

Options

Solution

Key Concepts and Formulas

  • De Morgan's Laws:
    • (pq)pq\sim(p \vee q) \equiv \sim p \wedge \sim q
    • (pq)pq\sim(p \wedge q) \equiv \sim p \vee \sim q
  • Negation of Negation: (p)p\sim(\sim p) \equiv p
  • Distributive Law: p(qr)(pq)(pr)p \vee (q \wedge r) \equiv (p \vee q) \wedge (p \vee r)

Step-by-Step Solution

Step 1: Write down the given Boolean expression. We begin by stating the expression we want to negate. E=s(rs)E = \sim s \vee (\sim r \wedge s)

Step 2: Negate the entire expression. We apply the negation to the given expression. E=(s(rs))\sim E = \sim (\sim s \vee (\sim r \wedge s))

Step 3: Apply De Morgan's Law. We use De Morgan's Law to distribute the negation across the 'or' operation. E=(s)(rs)\sim E = \sim (\sim s) \wedge \sim (\sim r \wedge s)

Step 4: Simplify the negation of negation. We simplify (s)\sim(\sim s) to ss. E=s(rs)\sim E = s \wedge \sim (\sim r \wedge s)

Step 5: Apply De Morgan's Law again. We use De Morgan's Law to distribute the negation across the 'and' operation inside the parentheses. E=s((r)s)\sim E = s \wedge (\sim (\sim r) \vee \sim s)

Step 6: Simplify the negation of negation again. We simplify (r)\sim(\sim r) to rr. E=s(rs)\sim E = s \wedge (r \vee \sim s)

Step 7: Apply the distributive law. We distribute ss across the 'or' operation. E=(sr)(ss)\sim E = (s \wedge r) \vee (s \wedge \sim s)

Step 8: Simplify sss \wedge \sim s. The expression sss \wedge \sim s is always false, which we represent as FF. E=(sr)F\sim E = (s \wedge r) \vee F

Step 9: Simplify the expression. Since anything 'or' false is itself, we have (sr)Fsr(s \wedge r) \vee F \equiv s \wedge r. E=sr\sim E = s \wedge r

Common Mistakes & Tips

  • Remember to apply De Morgan's Laws correctly. Pay attention to changing 'and' to 'or' and vice versa when negating.
  • Be careful with parentheses. Distribute the negation properly to all terms within the parentheses.
  • Recognize that ppp \wedge \sim p is always false (F) and ppp \vee \sim p is always true (T).

Summary

We started with the expression s(rs)\sim s \vee (\sim r \wedge s) and negated it. Using De Morgan's Laws and the distributive property, we simplified the negated expression step-by-step. We arrived at the simplified expression srs \wedge r, which represents the negation of the original expression.

Final Answer

The final answer is \boxed{s \wedge r}, which corresponds to option (D).

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