Skip to main content
Back to Mathematical Reasoning
JEE Main 2019
Mathematical Reasoning
Mathematical Reasoning
Easy

Question

Which of the following is equivalent to the Boolean expression p \wedge \sim q ?

Options

Solution

Key Concepts and Formulas

  • Logical AND (\wedge): The statement pqp \wedge q is true if and only if both pp and qq are true.
  • Logical NOT (\sim): The statement p\sim p is true if pp is false, and false if pp is true.
  • Logical Implication (pqp \to q): The statement pqp \to q is equivalent to pq\sim p \vee q. It is only false when pp is true and qq is false. We can also write (pq)pq\sim(p \to q) \equiv p \wedge \sim q.

Step-by-Step Solution

Step 1: Construct the truth table for pqp \wedge \sim q. We need to find the truth values for pp, qq, q\sim q and then pqp \wedge \sim q.

ppqqq\sim qpqp \wedge \sim q
TTFF
TFTT
FTFF
FFTF

Step 2: Construct the truth table for (qp)\sim (q \to p). First, we find qpq \to p, then we negate it.

ppqqqpq \to p(qp)\sim (q \to p)
TTTF
TFTF
FTFT
FFTF

Step 3: Construct the truth table for pq\sim p \to \sim q. First, we find p\sim p and q\sim q, then we find pq\sim p \to \sim q.

ppqqp\sim pq\sim qpq\sim p \to \sim q
TTFFT
TFFTT
FTTFF
FFTTT

Step 4: Construct the truth table for (pq)\sim (p \to \sim q). First, we find q\sim q, then pqp \to \sim q, and then (pq)\sim (p \to \sim q).

ppqqq\sim qpqp \to \sim q(pq)\sim (p \to \sim q)
TTFFT
TFTTF
FTFTF
FFTTF

Step 5: Construct the truth table for (pq)\sim (p \to q). First, we find pqp \to q, then we negate it.

ppqqpqp \to q(pq)\sim (p \to q)
TTTF
TFFT
FTTF
FFTF

Step 6: Compare the truth tables. We are looking for the option that has the same truth table as pqp \wedge \sim q. Comparing the truth tables from Steps 1-5, we see that (pq)\sim (p \to q) in Step 5 has the same truth table as pqp \wedge \sim q in Step 1.

ppqqpqp \wedge \sim q(qp)\sim (q \to p)pq\sim p \to \sim q(pq)\sim (p \to \sim q)(pq)\sim (p \to q)
TTFFTTF
TFTFTFT
FTFTFFF
FFFFTFF

We are given that the correct answer is (A), which corresponds to (qp)\sim (q \to p). However, the truth table for (qp)\sim (q \to p) does not match the truth table for pqp \wedge \sim q. There appears to be an error in the provided answer.

We see that the truth table for pqp \wedge \sim q is identical to the truth table for (pq)\sim (p \to q).

Common Mistakes & Tips

  • Remember the truth tables for basic logical operations (AND, OR, NOT, Implication).
  • When negating an implication, use the equivalence (pq)pq\sim (p \to q) \equiv p \wedge \sim q.
  • Be careful when constructing truth tables, especially with multiple negations or implications.

Summary

We constructed the truth tables for each of the given options and compared them to the truth table for pqp \wedge \sim q. By comparing the truth tables, we find that pq(pq)p \wedge \sim q \equiv \sim(p \to q). However, the question states that the correct answer is option (A), (qp)\sim(q \to p). There appears to be an error in the problem statement, as the correct answer should be option (D), (pq)\sim (p \to q).

Final Answer

The final answer is \boxed{D}, which corresponds to option (D).

Practice More Mathematical Reasoning Questions

View All Questions